Hi!
I can help you with joy!
The answer is 2x= 6x.
This is an example of direct variation!
Answer:
The answer to your question is None of the options, the answer is y ≥ 1
Step-by-step explanation:
Inequality
5 - 3 (y + 2) ≤ 6y - 10
1.- Expand
5 - 3y - 6 ≤ 6y - 10
2.- Simplify like terms
-3y - 1 ≤ 6y - 10
3.- Add -6y in both sides
- 3y - 6y - 1 ≤ 6y - 10 - 6y
4.- Simplify
-9y - 1 ≤ -10
5.- Add 1 in both sides
-9y - 1 + 1 ≤ -10 + 1
6.- Simplify
-9y ≤ -9
7.- Divide both sides by -9 and change ≤ by ≥
-9/-9 y ≥ -9/-9
8.- Simplify
y ≥ 1
Answer:
ohlkkkk
Step-by-step explanation:
but give your questions first
Answer:(a)x^2+2y^2=2
(b)In the attached diagram
Step-by-step explanation:Step 1: Multiply both equations by t
xt=t(cost -sint)\\ty\sqrt{2} =t(cost +sint)
Step 1: Multiply both equations by t
xt=t(cost -sint)\\ty\sqrt{2} =t(cost +sint)
Step 2:We square both equations
(xt)^2=t^2(cost -sint)^2\\(ty)^2(\sqrt{2})^2 =t^2(cost +sint)^2
Step 3: Adding the two equations
(xt)^2+(ty)^2(\sqrt{2})^2=t^2(cost -sint)^2+t^2(cost +sint)^2\\t^2(x^2+2y^2)=t^2((cost -sint)^2+(cost +sint)^2)\\x^2+2y^2=(cost -sint)^2+(cost +sint)^2\\(cost -sint)^2+(cost +sint)^2=2\\x^2+2y^2=2 hopes this helps
Answer:
free points thanks
Step-by-step explanation:
