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lions [1.4K]
3 years ago
15

Can someone please help me

Mathematics
1 answer:
STALIN [3.7K]3 years ago
4 0

Answer: (2,-4) is point a

Step-by-step explanation: when looking for a plotted point, the x axis can drop down to negatives since they y axis is negative

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2. What is 9 squared. <br> a. 3<br> b. 81<br> C. 18<br> O d. 11
vitfil [10]

Answer:

81

Step-by-step explanation:

6 0
3 years ago
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Which statements about the value of the digits in the number 6,666,666 are true?
tatiyna

B. The digit in the hundred thousands place is 1/10 the value of the digit in the millions place.

C. The digit in the ten thousands place is 10 times the value of the digit in the thousands place.

Hope this helps !

Photon
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3 years ago
If sine theta equals three over four, what are the values of cos θ and tan θ?
ratelena [41]

Answer:

In words, Cosine theta equals plus or minus square root of seven over 4,tangent theta equals plus or minus  three over root seven

Step-by-step explanation:

Given that sin ∅ =3/4 It means the ratio of the opposite side to the hypotenuse side is 3:4.

Using the Pythagoras theorem we can calculate the hypotenuse adjacent as follows.

a²+b²=c²

a²=c²-b²

a²=4²-3²

a²=16-9

a²=7

a=√7

Then Cos ∅= opposite/ adjacent

=√7/4

Then Tan ∅ = opposite/adjacent

=3/√7

In words, Cosine theta equals plus or minus square root of seven over 4,tangent theta equals plus or minus  three over root seven.

7 0
3 years ago
Write a vector equation of the line that passes through point P(-4,11) and is parallel to a=[-3,8]. Then write parametric equati
Assoli18 [71]

Answer:

\vec l = (-4, 11) + t\cdot (-3,8), x = -4 - 3\cdot t and y = 11 + 8\cdot t

Step-by-step explanation:

The vector equation of the line is:

\vec l = \vec P + t \cdot \vec A

\vec l = (-4, 11) + t\cdot (-3,8)

The parametric equations of the line are:

x = -4 - 3\cdot t and y = 11 + 8\cdot t

4 0
3 years ago
7/9+5/6·1/3<br> write it in simplest form
Talja [164]

Answer:

19/18

Step-by-step explanation:

simplify x/3

simplify 5/6

simplify 7/9

8 0
3 years ago
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