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UNO [17]
3 years ago
7

How much pure alcohol must be added to 400 ml of a 15% solution to make its strength 32%

Mathematics
1 answer:
NISA [10]3 years ago
6 0
Quantity of alcohol =400*15/100 = 60ml
x is <span>pure alcohol which must be added : (x + 60)/(x + 400) = 32/100
100x + 6000 = 32x + 12800 => 68x = 6800 => x = 100
100ml pure alcohol must be added

</span>
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▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

In the number line attached in my attachment,

The red line represents point :

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3 0
2 years ago
How do I solve this?
Kryger [21]
     y = abˣ
   20 = ab¹
   20 = ab
    b      b
20/b = a

 y = abˣ
 4 = (20/b)b²
 4 = 20b
20    20
¹/₅ = b

   y = abˣ
 20 = ¹/₅b¹
 20 = ¹/₅b
  ¹/₅     ¹/₅
100 = b

y = abˣ
y = 100(0.2)ˣ
4 0
3 years ago
Sorry that the pic is upside down <br>ANSWER IT PLS<br>NO LINKS​
ki77a [65]
The answers to that question is 75 degreey
7 0
2 years ago
How do I solve this?
EastWind [94]

Answer:

i think that you have to divide each fraction, andmaybe find the other fractions

Step-by-step explanation:

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