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3 years ago

(this is 12 year old math) Good evening everyone

Mathematics

2 answers:

Ilya [14]3 years ago

6 0

Answer:

22 11

Step-by-step explanation:

gtnhenbr [62]3 years ago

3 0

Answer:

22 11

Step-by-step explanation:

its a pattern if you look at the trend on the equation

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Which quadrant contains the vertex of the following: f(x) =–2x² –8x+11

leonid [27]

Quadrant 2 contains the vertex of f(x)=-2x^2-8x+11

4 0

3 years ago

On a baseball

vampirchik [111]

Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.

<h3>How far did the outfielder throw the ball?</h3>

Based on the shape of a mound, the law of cosines can be used.

The distance the ball was thrown by the outfielder can therefore be d.

Distance is:

d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))

d ²= 33,484.42ft

Then find the square root:

d = √33,484.42

= 182.9874

= 183 ft

Find out more solving for distance at brainly.com/question/10739348

#SPJ1

4 0

2 years ago

the table tells us that 4 students had no siblings 5 students had one sibling, 14 students had two siblings and so on

Hatshy [7]

The answer is 8000383890

7 0

3 years ago

An object in geometry with no width, length or height is a(n):

il63 [147K]

Answer:

Point

Step-by-step explanation:

Just see it like this

we have a cube, so we have x-, y- and z- axis.

Now if we divide this cube by its z- value we will have a 2 dimensional figure with x- and y- axis.

If we keep doing this we will have a 1 dimensional figure with only a x - axis (a line) and if we divide that 1 more time we will make the figure collapse in 1 point.

6 0

3 years ago

mrs.beluga is driving on a snow covered road with a drag factor of 0.2. she brakes suddenly for a deer. The tires leave a yaw ma

Aneli [31]

First, we are going to find the radius of the yaw mark. To do that we are going to use the formula: $r= \frac{c^2}{8m} + \frac{m}{2}$
where
$c$ is the length of the chord
$m$ is the middle ordinate
We know from our problem that the tires leave a yaw mark with a 52 foot chord and a middle ornate of 6 feet, so $c=52$ and $m=6$ . Lets replace those values in our formula:
$r= \frac{52^2}{8(6)} + \frac{6}{2}$
$r= \frac{2704}{48} +3$
$r= \frac{169}{3} +3$
$r= \frac{178}{3}$

Next, to find the minimum speed, we are going to use the formula: $s= \sqrt{15fr}$
where
$f$ is <span>drag factor
</span> $r$ is the radius
We know form our problem that the drag factor is 0.2, so $f=0.2$ . We also know from our previous calculation that the radius is $\frac{178}{3}$ , so $r= \frac{178}{3}$ . Lets replace those values in our formula:
$s= \sqrt{(15)(0.2)( \frac{178}{3}) }$
$s= \sqrt{178}$
$s=13.34$ mph

We can conclude that Mrs. Beluga's minimum speed before she applied the brakes was 13.34 miles per hour.

8 0

3 years ago

(this is 12 year old math) Good evening everyone​

(this is 12 year old math) Good evening everyone