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Black_prince [1.1K]
3 years ago
15

Who wanna give me the answer ;)

Mathematics
1 answer:
patriot [66]3 years ago
6 0

Answer:

D

Step-by-step explanation:

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Simplify 0.363635 to the nearest tenths
Andrews [41]
The answer will be 0.4 just round 0.36 the 6 will go up making the 6 into a 0 and the 3 into a 4
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Why was my sister freaking boohoo crying (made me sad) over a pet rat that shes had for like a year and he's getting old he got
Reptile [31]

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wait a rat as a pet naw rats are just cat food

Step-by-step explanation:

4 0
3 years ago
A picture frame is 16 inches long and 9 inches tall. It is 2 inches wide on all 4 sides. What is the area of the picture frame?
Ira Lisetskai [31]
Area of frame=area of total-area of inside ting

area=lenght times width
so

inner one
length is 16-2-2 (both sides) or 12
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outter one
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4 0
3 years ago
Rudy has been paying an annual homeowners insurance premium of $1,106.30 ($0.37 per $100 of value) since he first purchased his
iren [92.7K]

If Rudy successfully adds $50,000 to the value of his house, his new annual homeowner's insurance premium be <u>c. $1,291.30</u>.

<h3>What is the annual homeowner's insurance premium?</h3>

The annual homeowner's insurance premium is the insurance charge that the homeowner pays as an insurance premium annually.

The insurance premium is calculated using some set formulas determined by these factors:

  • Home's value
  • Location
  • Coverage Value
  • Safety features
  • Deductibles.

<h3>Data and Calculations:</h3>

Insurance premium rate = $0.37 per $100

Current insurance premium = $1,106.30

Added value to the house = $50,000

Added premium = $185 ($50,000 x $0.37/$100)

New insurance premium = $1,291.30 ($1,106.30 + $185)

Thus, if Rudy successfully adds $50,000 to the value of his house, his new annual homeowner's insurance premium be <u>c. $1,291.30</u>.

Learn more about the annual homeowner's insurance premium at brainly.com/question/26133348

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8 0
2 years ago
9 cm
OLEGan [10]

Answer:

∴ ∠BAD = sin^{-1}(0.2044) = 11.8°

Step-by-step explanation:

i) AD = 9 cm

ii) DC = 3 cm

iii) ∠BCD = 35°

iv) Since AB is parallel to DC and ∠ABD = 90°  then we can conclude that ∠BDC = 90°.

v) \frac{BD}{DC}  =  \frac{BD}{3\hspace{0.1cm}cm}  = tan(35) = 0.6128      ∴ BD  = 3 \times 0.6128 = 1.84 cm

vi) ∴ sin(∠ BAD ) = \frac{BD}{AD}      ⇒     sin(∠ BAD ) = \frac{1.84}{9} = 0.2044

     ∴ ∠BAD = sin^{-1}(0.2044) = 11.8°

7 0
4 years ago
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