Answer: 0.50477
Step-by-step explanation:
Given : The sugar content of the syrup is canned peaches is normally distributed. 
We assume the can is designed to have standard deviation  milligrams.
 milligrams. 
The sampling distribution of the sample variance is chi-square distribution.
Also,The data yields a sample standard deviation of  milligrams.
 milligrams.
Sample size : n= 10
Test statistic for chi-square :
i.e. 
Now, P-value =  [By using the chi-square distribution table for p-values.]
  [By using the chi-square distribution table for p-values.]
Hence, the chance of observing the sample standard deviation greater than 4.8 milligrams = 0.50477
 
        
             
        
        
        
Answer:

Step-by-step explanation:

 
        
                    
             
        
        
        
Answer:
D
Step-by-step explanation:
step 2 : x + 3 = 0 and x - 5 = 0 ← correct
step 3 
x = 3 and x = - 5 ← error made here with signs, correct statement should be
x + 3 = 0 ⇒ x = - 3
x - 5 = 0 ⇒ x = 5
 
        
             
        
        
        
Answer:
The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of  , and a confidence level of
, and a confidence level of  , we have the following confidence interval of proportions.
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of  .
.
For this problem, we have that:

99% confidence level
So  , z is the value of Z that has a pvalue of
, z is the value of Z that has a pvalue of  , so
, so  .
.
The lower limit of this interval is:

The upper limit of this interval is:

The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).