For a 1st order reaction:
In(n/n0)= -k * (time difference)
so k= - In (n/n0)/ (t/t0)
n is concentration at time t and n0 is the concentration at an earlier time t0.
where k is constant.
The two resonating structures of Nitrous Acid are shown below. Lone pair of electrons, single and multiple bonds and non zero formal charges (red color) are also specified.
Among these two structures the structure on the left lacking formal charge is the most stable form. The instability of second resonating structure is due to the fact that it contains two formal charges (the lesser the number of formal charges the greater is the stability). Secondly in this structure one oxygen atom is having +1 formal charge. Oxygen being more electronegative feel hostile towards positive formal charge.
Answer:
Linear combination of atomic orbitals (LCAO) is a simple method of quantum chemistry that yields a qualitative picture of the molecular orbitals (MOs) in a molecule. Let us consider H
+
2
again. The approximation embodied in the LCAO approach is based on the notion that when the two protons are very far apart, the electron in its ground state will be a 1s orbital of one of the protons. Of course, we do not know which one, so we end up with a Schrödinger cat-like state in which it has some probability to be on one or the other.
As with the HF method, we propose a guess of the true wave function for the electron
ψg(r)=CAψ
A
1s
(r)+CBψ
B
1s
(r)
where ψ
A
1s
(r)=ψ1s(r−RA) is a 1s hydrogen orbital centered on proton A and ψ
B
1s
(r)=ψ1s(r−RB) is a 1s hydrogen orbital centered on proton B. Recall ψ1s(r)=ψ100(r,ϕ,θ). The positions RA and RB are given simply by the vectors
RA=(0,0,R/2)RB=(0,0,−R/2)
The explicit forms of ψ
A
1s
(r) and ψ
B
1s
(r) are
ψ
A
1s
(r) =
1
(πa
3
0
)1/2
e−|r−RA|/a0 ψ
B
1s
(r) =
1
(πa
3
0
)1/2
e−|r−RB|/a0
Now, unlike the HF approach, in which we try to optimize the shape of the orbitals themselves, in the LCAO approach, the shape of the ψ1s orbital is already given. What we try to optimize here are the coefficients CA and CB that determine the amplitude for the electron to be found on proton A or proton B.
Explanation:
This means that the mass of one mole of aluminium atoms will be 26.982 g . As you know, one mole of any element contains exactly 6.022⋅1023 atoms of that element.
Answer:
I think the answer would be b, sorry if I'm wrong(EDIT: ITS ACTUALLY AAAAA)