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weeeeeb [17]
2 years ago
5

How many grams of KOH are required to prepare 500. mL of 0.450 KOH solution?

Chemistry
1 answer:
Digiron [165]2 years ago
5 0

Answer:

KOH  molar mass = 39 + 16 + 1 = 56g

To make 1 L of 1M soln needs 56g KOH

To make 500mL 1M needs 56/2 = 28g

To make 500mL 0.2M needs 28 x 0.2gn:

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What is the percent composition each element in c6h8o6
QveST [7]

Answer:

Percentage of oxygen = 30%

Percentage of carbon = 30%

Percentage of hydrogen = 40%

Explanation:

Formula:

Percentage of element = given amount / total amount × 100

Given compound:

C₆H₈O₆

Number of atoms of carbon = 6

Number of atoms of hydrogen = 8

Number of atoms of oxygen = 6

Total number of atoms = 20

Percentage of carbon = 6/20 × 100

Percentage of carbon = 30%

Percentage of Hydrogen = 8/20 × 100

Percentage of Hydrogen = 40%

Percentage of oxygen = 6/20 × 100

Percentage of oxygen = 30%

6 0
3 years ago
PLEASE HELP!!!! i give a lot of points
hammer [34]
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5 0
2 years ago
If the volume of wet gas collected over water is 85.0 mL at 20°C and 760 mm Hg , what is the volume of dry gas at STP conditions
dimulka [17.4K]

Answer: 77.4 mL

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of dry gas = (760 - 17.5) mmHg= 742.5 mm Hg

P_2 = final pressure of dry gas at STP =  760 mm Hg

V_1 = initial volume of dry gas = 85.0 mL

V_2 = final volume of dry gas at STP = ?

T_1 = initial temperature of dry gas = 20^oC=273+20=293K

T_2 = final temperature of dry gas at STP = 0^oC=273+0=273K

Now put all the given values in the above equation, we get the final volume of wet gas at STP

\frac{742.5mmHg\times 85.0ml}{293K}=\frac{760mmHg\times V_2}{273K}

V_2=77.4mL

Volume of dry gas at STP is 77.4 mL.

5 0
3 years ago
Choose the answer that best completes the following statement: When an aluminum atom reacts so as to attain a noble gas electron
boyakko [2]

The options

Select one:

a. a 3- ion forms.

b. the noble gas configuration of argon is achieved.

c. the result is a configuration of 1s2 2s2 2p6.

d. the atom gains five electrons.

Answer:

c. the result is a configuration of 1s2 2s2 2p6.

Explanation:

Aluminium atom has atomic number of 13 , hence the number of electron is 13 for a neutral atom of aluminium. When aluminium atom reacts with other elements it usually gives out three electron to attain the octet configuration.

The cation representation of aluminium is Al3+ because it has loss three electron to attain the octet rule. Aluminium will be left with 10 electrons after losing 3 of it electrons. The electronic configuration will be represented as follows after losing three electrons;

1S² 2S² 2P∧6 .

At this stage the octet rule has been achieved as it will be represented as

2  8.  The first energy shell now contains two electron and the second energy shell contains 8 electrons.

The configuration of  Neon has been formed in the process.

4 0
3 years ago
How would granite be classified as
vredina [299]

Answer:

Granite is an intrusive igneous rock which means it is cooled slowly deep upper the Earth's crust. It is composed of 25% to 35% quartz and over 50% potassium- and sodium rich feldspars.

Explanation:

4 0
2 years ago
Read 2 more answers
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