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storchak [24]
3 years ago
13

Compound w , c6h13cl, undergoes base-promoted e2 elimination to give a single c6h12 alkene, y. compound x, c6h13br, undergoes a

similar reaction to form y and an isomeric alkene z. w is chiral; x is not. catalytic hydrogenation of y and z produces 2-methylpentane. propose structures for w and x.
Chemistry
1 answer:
CaHeK987 [17]3 years ago
5 0
<span>Answer: W must be 5-chloro-2-methylpentane. It can give only 4-methy-1-pentene (Y) upon dehydrohalogenation: X must be 4-chloro-2-methylpentane. Dehydrohalogenation yields both Y and 4-methyl-2-pentene. (Z)</span>
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What is the hydronium ion concentration of a solution whose pH is 7.30
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[ H₃O⁺] = 10 ^ - pH

[ H₃O⁺ ] = 10 ^ - 7.30

[ H₃O⁺ ] = 5.011 x 10⁻⁸ M

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What is the percentage by mass of sulphur in Al2(SO4)3[A12SO4 =<br>342g/mol, S = 32]​
valentinak56 [21]

Answer: The percentage by mass of sulphur in Al_2(SO_4)_3 is 9.36%

Explanation:

Mass percent of an element is the ratio of mass of that element by the total mass expressed in terms of percentage.

{\text {Mass percentage}}=\frac{\text {mass of sulphur}}{\text {Total mass}}\times 100\%

Given: mass of sulphur = 32 g/mol

mass of Al_2(SO_4)_3 = 342 g/mol

Putting in the values we get:

{\text {Mass percentage}}=\frac{32g/mol}{342g/mol}\times 100\%=9.36\%

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4 0
3 years ago
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Scorpion4ik [409]

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7 0
3 years ago
Consider the balanced equation for the following reaction:
Bad White [126]

<u>Answer:</u> The theoretical yield of the lithium chlorate is 1054.67 grams

<u>Explanation:</u>

To calculate the mass for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Actual moles of lithium chlorate = 9.45 moles

Molar mass of lithium chlorate = 90.4 g/mol

Putting values in above equation, we get:

9.45mol=\frac{\text{Actual yield of lithium chlorate}}{90.4g/mol}\\\\\text{Actual yield of lithium chlorate}=(9.45mol\times 90.4g/mol)=854.28g

To calculate the theoretical yield of lithium chlorate, we use the equation:

\%\text{ yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100

Actual yield of lithium chlorate = 854.28 g

Percentage yield of lithium chlorate = 81.0 %

Putting values in above equation, we get:

81=\frac{854.28g}{\text{Theoretical yield of lithium chlorate}}\times 100\\\\\text{Theoretical yield of lithium chlorate}=\frac{854.28\times 100}{81}=1054.67g

Hence, the theoretical yield of the lithium chlorate is 1054.67 grams

7 0
3 years ago
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