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storchak [24]
3 years ago
13

Compound w , c6h13cl, undergoes base-promoted e2 elimination to give a single c6h12 alkene, y. compound x, c6h13br, undergoes a

similar reaction to form y and an isomeric alkene z. w is chiral; x is not. catalytic hydrogenation of y and z produces 2-methylpentane. propose structures for w and x.
Chemistry
1 answer:
CaHeK987 [17]3 years ago
5 0
<span>Answer: W must be 5-chloro-2-methylpentane. It can give only 4-methy-1-pentene (Y) upon dehydrohalogenation: X must be 4-chloro-2-methylpentane. Dehydrohalogenation yields both Y and 4-methyl-2-pentene. (Z)</span>
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In the second compound;

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The Formular is WCl₄

In the third compound;

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Total mass of compound = 361.42 g

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The Formular is WCl₅

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The Formular is WCl₆

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3 years ago
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