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Yuliya22 [10]
3 years ago
8

How many grams of calcium chloride were used if 2.485 grams of calcium oxalate monohydrate were produced, assuming a 100% yield.

This means all of the calcium chloride was converted to calcium oxalate monohydrate. Report your answer to 3 decimal places in grams.
Chemistry
1 answer:
DochEvi [55]3 years ago
5 0

Answer:

54 G

Explanation:

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How to calculate the frequency of an ion
sergij07 [2.7K]

solution:

You need to find the frequency, and they have already given you the wavelength. And since you already know the speed of light, you can use formula (2) to answer this problem. Remember to convert the nano meters to meters because the speed of light is in meters. (1 nm = 1.0 x 10^{-9} m)

v=c\lambda \\v= (3.00 \times 10^8 m/s)/(6.9\times 10^-7 m) \\v = 4.35 \times 10^{14} s^{-1}

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3 years ago
According to Dalton, what happens to atoms during a chemical reaction? Atoms gain or lose energy. Atoms are rearranged. Old atom
Hunter-Best [27]

Answer:

Atoms are rearranged.

Explanation:

7 0
3 years ago
The modern view of an electron orbital in an atom is best described as
Mrrafil [7]

invisable

you probably dont want to put that...

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3 years ago
What volume of 0.585 m ca(oh)2 would be needed to neutralize 15.8 l of 1.51 m hcl?
SpyIntel [72]
When the balanced reaction equation is:

2HCl(aq) + Ca(OH)2(aq) → CaCl2(aq) + 2H2O(l)

from the balanced equation, we can get the molar ratio between HCl & Ca(OH)2

2:1

∴ the volume of Ca(OH)2 = 15.8 L HCl * 1.51 m HCl * (1mol Ca(OH)2/ 2mol HCl) *                                           (1L ca(OH)2/0.585 mol Ca(OH)2 

                                          = 20.4 L
8 0
3 years ago
Which element is the excess reagent when 3.00 moles of Mg is ignited in 2.20 moles of pure oxygen
Artyom0805 [142]

Answer:

Oxygen is in excess.

Explanation:

The coefficients of the balanced equation create a mole ratio that shows the ratio of how many reactants are used up and products are created.  

The mole ratio of Mg to O2 in this equation is 2:1, which means that for every two moles of Mg used, there will be 1 mole of O2 used.

If we have 3.00 moles of Mg, we will only need 1.5 moles of oxygen to completely burn the Mg. Therefore, when all 3.00 moles of Mg are used, there will still be some of the 2.20 moles of oxygen remaining.

7 0
2 years ago
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