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lubasha [3.4K]
3 years ago
15

An online auction charges sellers a flat fee of $1.20 and 2% of the amount of the sale. Let A be the amount of the sale in dolla

rs and C be the charge of the online auction. Explain whether the solutions A=−5 and C=1.1 are viable.
The solutions are not viable because the amount charged is not a whole number.

The solutions are viable because the amount of the sale is an integer.

The solutions are viable because the amount charged is positive.

The solutions are not viable because the amount of the sale cannot be negative
Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
3 0

Answer:

The solutions are not viable because the amount of the sale cannot be negative

Step-by-step explanation:

We are told that;

Let A be the amount of the sale in dollars and C be the charge of the online auction

This means that both values of A and B should be non-negative integers.

Now, we are also told that An online auction charges sellers a flat fee of $1.20 and 2% of the amount of the sale.

We can conclude that the solution is not viable because the amount of sale of -1.1 cannot be negative.

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small cubes with edge lengths of 1/4 inch will be packed into the right rectangular prism shown.( the base is 4 1/2, the width i
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General Idea:

We need to find the volume of the small cube given the side length of the small cube as 1/4 inch.

Also we need to find the volume of the right rectangular prism with the given dimension (the height is 4 1/2, the width is 5, and the length is 3 3/4).

To find the number of small cubes that are needed to completely fill the right rectangular prism, we need to divide volume of right rectangular prism by volume of each small cube.

Formula Used:

Volume \; of \; Cube = a^3 \; \\\{where \; a \; is \; side \; length \; of \; cube\}\\\\Volume \; of  \; Right \; Rectangular  \; Prism=L \times W \times H\\\{Where  \; L \; is \; Length, \; W \; is \; Width, \;and  \; H \; is \; Height\}

Applying the concept:

Volume of Small Cube:

V_{cube}= (\frac{1}{4}  )^3= \frac{1}{64} \; in^3\\\\V_{Prism}=  3 \frac{3}{4}  \times 5 \times  4 \frac{1}{2}  = \frac{15}{4}  \times \frac{5}{1}  \times \frac{9}{2}  = \frac{675}{8}  \\\\Number \; of \; small \; cubes= \frac{V_{Prism}}{V_{Cube}}   = \frac{675}{8}  \div \frac{1}{64}  \\\\Flip \; the \; second \; fraction\; and \; multiply \; with \; the \; first \; fraction\\\\Number \; of \; small \; cubes \;= \frac{675}{8} \times \frac{64}{1}   = 5400

Conclusion:

The number of small cubes with side length as 1/4 inches that are needed to completely fill the right rectangular prism whose height is 4 1/2 inches, width is 5 inches, and length is 3 3/4 inches is <em><u>5400 </u></em>

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