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2 years ago

Describe the error in the work shown. 62 + 3 + 5 x 2 36 + 8 x 2 36 + 16 52

Mathematics

1 answer:

makkiz [27]2 years ago

6 0

Answer:

There is an error in the application of the DMAS rule, The answer as per the DMAS rule is 75.

Step-by-step explanation:

There is an error in the implication of the DMAS rule of Mathematics.

DMAS rule determines the arrangement of mathematical functions to be performed in an expression where multiple functions are present.

The DMAS Rules describes the following arrangement of the mathematical functions.

1st Division

2nd Multiplication

3rd Addition

4th Subtraction

Applying the above rule the solution is as follow

62 + 3 + 5 x 2

First, we need to solve the Multiplication because there is no division

62 + 3 + 10

Now perform the addition function

65 + 10

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I believe it's 15, but correct me if I'm wrong
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2 years ago

Sammy counts the number of people in one section of the school auditorium. He counts 18 female students, 16 male students, and 6

Rzqust [24]

Correct Question:

He counts 18 female students, 16 male students, and 6 teachers. There are

720 people in the auditorium. Consider the probability of selecting one person

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Which of these statements are true?

Choose all that apply.

A: The probability of selecting a teacher is 6%.

B : The probability of selecting a student is 85%.

C : The probability of selecting a male student is 32%.

D : The probability of selecting a female student is 45%.

Step-by-step explanation:

Option B and D are correct because

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A = The probability of selecting a teacher is = (6/40)x100 = 15 % not equal to 6 %

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C = The probability of selecting a male student is = (16/40)x100 = 40 % not equal to 32 %

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2 years ago

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Step-by-step explanation:

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3 years ago

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The managers of 21 supermarkets counted the number of cars in their parking lots on the same day. The results are shown in the l

mixer [17]

The IQR is 42.5

Step-by-step explanation:

Interquartile range is the difference of third and first quartile.

First of all we have to find the median for that purpose the data has to be arranged in ascending order. The data is already in ascending order.

As the number of values are odd

n=21

The median will be: $(\frac{n+1}{2}) th\ term$

Putting n=21

$(\frac{21+1}{2})th\ term\\=(\frac{22}{2})th\ term\\= 11th\ term$

The 11th term is 133

So median = 133

Now the data is divided into two halves

One is: 98, 100, 101, 102, 108, 109, 111,118, 129, 132

2nd is: 135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q1 will be the median of first half and Q3 will be the median of 2nd half.

As now the halves contain even number of values, the medians will be the average of middle two values

For First Half:

98, 100, 101, 102, 108, 109, 111,118, 129, 132

$Q_1 = \frac{108+109}{2}\\Q_1 = \frac{217}{2}\\Q_1 = 108.5$

For Second Half:

135, 135, 145, 146, 146, 156, 170 176, 180, 180

$Q_2 = \frac{146+156}{2}\\Q_2 = \frac{302}{2}\\Q_2 = 151$

Now

Interquartile Range:

$IQR = Q_3-Q_1\\= 151-108.5\\=42.5$

Hence,

The IQR is 42.5

Keywords: Median, IQR

Learn more about median at:

#LearnwithBrianly

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3 years ago

Describe the error in the work shown. 62​ + 3 + 5 x 2 ​ ​ 36 + 8 x 2 ​36 + 16 52

Describe the error in the work shown. 62 + 3 + 5 x 2 36 + 8 x 2 36 + 16 52