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garik1379 [7]
3 years ago
11

If f(x) = -4x + 3 and g(x) = 3x^2 + 2x - 4 find (f+g) (x)

Mathematics
1 answer:
Ivenika [448]3 years ago
5 0

Answer:

3x^2-2x-1

Step-by-step explanation:

Here, we want to find (f + g)(x)

Mathematically, that will be f(x) + g(x)

= -4x + 3 + 3x^2 + 2x -4

= -2x-1 + 3x^2

= 3x^2-2x-1

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If h(x) is the inverse of f(x), what is the value of h(f(x))?
Mekhanik [1.2K]
Hello,

f(x) has as inverse f^(-1)(x)
and (fof^(-1))(x)=(f^(-1)of)(x)= x (the neutral function)
so h(f(x))=x

8 0
3 years ago
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Find the value of X or Y so that the line through the points has the given slope. (X, 0) and (4,1); slope: 1/5
Ronch [10]
Point slope formula:
(y₂ -y₁) = m(x₂ - x₁)
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8 0
3 years ago
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kotykmax [81]

Answer:

These should be right hopefully! Hope it helps!

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6 0
3 years ago
Andy completes the square for the equation x2 + 6x - 8 = 0. Which of the following equations reveals the vertex of the parabola?
Stolb23 [73]
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x^2+6x-8

x^2+6x+9-8-9
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3 years ago
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Simplify the number into simplest radical form. Use the factor tree to help determine the factors. StartRoot 96 Endroot StartRoo
NikAS [45]

Answer:

[tex]4608\sqrt{3}[/tex]

Step-by-step explanation:

1. \sqrt{96} *\sqrt{6}* 2*\sqrt{6}*4 *\sqrt{6} *4*\sqrt{3}

2. \sqrt{2^{5} *3} \sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}   <em>factoring 96</em>

<em>since \sqrt{2^{5}*3 } = \sqrt{2^{5} } \sqrt{3}</em>

3. \sqrt{2^{5} } \sqrt{3}\sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}

<em>using exponent rule - (a^{b}) ^{c} = a^{bc}</em>

<em> \sqrt{2^{5} } = 2^{5/2}</em>

4. 2^{5/2}\sqrt{3}\sqrt{2*3} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}

<em>doing some simple simplification and 4=2^{2}  and 6=2*3</em>

5. 2^{5/2} \sqrt{3} \sqrt{2} \sqrt{3} *2\sqrt{2} \sqrt{3} *2^{2}\sqrt{2} \sqrt{3}*4\sqrt{3}

<em>collecting the roots on one side and applying exponent rule</em>

6. \sqrt{3} \sqrt{3}\sqrt{3} \sqrt{3}\sqrt{2} \sqrt{2}\sqrt{2} *2^{5/2+1+2+2} \sqrt{3}

<em>Applying exponents rule on all \sqrt{3} and \sqrt{2}</em>

<em>7. 2^{1/2+1/2+1/2} *2^{5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}</em>

<em>combining all powers of 2</em>

8. 2^{1/2+1/2+1/2+5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}

<em>Simplifying</em>

9. 2^{9} *3^{2}\sqrt{3}

10. 512*9\sqrt{3}

11. 4608\sqrt{3}

3 0
3 years ago
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