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Ugo [173]
3 years ago
8

What is the slope of a line perpendicular to the line whose equation is x-y=6x. Fully reduce your answer.

Mathematics
2 answers:
Over [174]3 years ago
5 0

Answer  

1/5

Step-by-step explanation:

The slope of a perpendicular line is the negative reciprocal. Since y=-5x(m=-5), the slope is -(-1/5) which is 1/5

Wittaler [7]3 years ago
3 0
<h3><u>Answer:</u></h3>

\boxed{\boxed{\pink{\bf \leadsto Hence \ the \   Slope \ the \ line \ is \ \dfrac{1}{5} . }}}

<h3><u>Step-by-step explanation:</u></h3>

A linear equation is given to us and we need to find the slope of the line perpendicular to it . Given linear equation to us is ,

\bf\implies x - y = 6x

Let's convert this into Slope intercept form to find the slope of the line . The slope intercept form is y = mx + c , where m is the slope of the line.

\bf\implies x - y = 6x \\\\\bf\implies x - y -6x = 0  \\\\\bf\implies- y - 5x = 0  \\\\\bf\implies y = -5x  \\\\\bf\implies \boxed{\red{\bf y = -5x + 0 }}

Hencs on comparing to the standard form of Slope intercept form of the line , we get to know that the slope of the line is -5.

The equation of a perpendicular line to y = -5x

must have a slope that is the negative reciprocal of the original slope. Hence ,

\bf\implies m_{perpendicular}= - \dfrac{1}{m}\\\\\bf\implies m_{perpendicular}= -\dfrac{1}{-5}\\\\\bf\implies \boxed{\red{\bf Slope_{perpendicular}= \dfrac{1}{5} }}

<h3><u>★</u><u> </u><u>Hence </u><u>the</u><u> </u><u>slope </u><u>of</u><u> </u><u>the </u><u>line </u><u>is⅕</u><u>.</u></h3>
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siniylev [52]

Answer:

The statement is false.

Step-by-step explanation:

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6 0
3 years ago
How to solve this one​
ladessa [460]

A dotted line is not included in the solution so there is no equal sign.

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4 0
3 years ago
The graph below shows the line of best fit for data collected on the number of cell phones and cell phone cases sold at a local
Dovator [93]

Answer:

C

Step-by-step explanation:

The equation of a line is given by y-y_1=m(x-x_1)

and

slope (m) is given by:

m=\frac{y_2-y_1}{x_2-x_1}

Where (x_1,y_1) are the first set of point in the line and (x_2,y_2) is the second set of point

<em>Let's take 2 points arbitrarily. (0,0) & (25,20)</em>

<em />

<em>Let's plug it and find the equation:</em>

<em>m=\frac{20-0}{25-0}=0.8</em>

<em>Now</em>

<em>y-y_1=m(x-x_1)\\y-0=0.8(x-0)\\y=0.8x</em>

<em />

<em>C is the correct answer.</em>

5 0
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Read 2 more answers
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