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cricket20 [7]
3 years ago
11

In triangle RST, angle R is a right angle. If TR = 6 and TS = 8, what is the length of RS

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
8 0

Answer:

RS = 2\sqrt{7}

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

RS² + RT² = TS² , that is

RS² + 6² = 8²

RS² + 36 = 64 ( subtract 36 from both sides )

RS² = 28 ( take the square root of both sides )

RS = \sqrt{28} = \sqrt{4(7)} = 2\sqrt{7} ≈ 5.3 ( to 1 dec. place )

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Answer:

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Step-by-step explanation:

As FH bisects ∠EFG , ∠EFH = ∠HFG .

We know that ∠EFH = (-5x + 89)° . So ∠HFG = ∠EFH = (-5x + 89)°

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