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Scorpion4ik [409]
3 years ago
12

What is the sum of the first five terms of a geometric series with a1 = 20 and r = 1/4?

Mathematics
1 answer:
____ [38]3 years ago
4 0
Sum of the first n terms of a geometric sequence is Sn = a(1 - r^n)/(1 - r)
Sn = 20(1 - (1/4)^5)/(1 - 1/4) = 20(1 - 1/1024)/(3/4) = 20(1023/1024)/(3/4) = 26 41/64
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Andy is solving a quadratic equation using completing the square. If a step in the process results in 169/9 = (x – 6)2, could th
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Given m|n, find the value of x.
yaroslaw [1]
X=12


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<img src="https://tex.z-dn.net/?f=%2826%20%5Cdiv%20100%29%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5Ctimes%2010" id
taurus [48]

Answer:

\boxed{\bf \:  \cfrac{13}{5}}

<u>Or in Decimal:</u>

\boxed{\bf \: 2.6}

Step-by-step explanation:

<u>Given expression :-</u>

\sf \: ( 26 \div 100) \times 10

<u>Solution :-</u>

\sf  = (26 \div 100 )\times 10

This arithmetic expression may be rewritten as ;

\sf  =  \cfrac{26}{100}  \times 10

Step 1 : <u>Cancel the zero of 10 and one zero of 100</u> :-

\sf  =  \cfrac{26}{10 \cancel0}  \times 1 \cancel0

<em>Results to;</em>

\sf  =  \:  \cfrac{26}{10}  \times 1

\sf  =  \:  \cfrac{26}{10}

Step 2: <u>Cancel 26 and 10</u><u> </u><u>by 2</u> :-

\sf  =  \cfrac{ \cancel{26}}{ \cancel{10}}

<em>Results to;</em>

\sf = \cfrac{ \cancel{26} {}^{13} }{ \cancel{10} {}^{5} }

\sf  =  \cfrac{13}{5}

<em>It can also be in Decimal.</em>

That is;

\sf = 2.6

Hence, the answer of the expression would be 13/5 or 2.6 .

\rule{225pt}{2pt}

I hope this helps!

Let me know if you have any questions.

I am joyous to help!

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Any number above 1 gets greater, below 1 smaller (when above 0), while 1 itself remains the same. Negative numbers are more unpredictable.
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At three hours as car a has already traveled a hour which making it three therefore making car b equal 2 hours or in a math equation 40×3=car b and 60×2=car a
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