Answer:
3.
Step-by-step explanation:
Divide the day price by the week and round down.
You get like 3.45, so 3.
<em>hope this helps :)</em>
The question is incomplete :
The height, width and Lenght isn't Given. However, we can create an hypothetical scenario, with a height 6, length 8 and width 4
Answer:
192 unit³
Step-by-step explanation:
The volume of the card box :
Recall the volume of box formula :
V = length * width * height
Volume = 8 * 6 * 4
Volume = 192 unit³
This is the procedure for any given dimension of the card deck.
Answer: V = (12in - 2*x)*(8 in - 2*x)*x
Step-by-step explanation:
So we have a rectangular cardboard sheet, and we cut four squares of side length x in each corner so we can make a box.
Remember that for a box of length L, width W and height H, the volume is:
V = L*W*H
In this case, the length initially is 12 inches, but we remove (from each end) x inches of the length, then the length of the box will be:
L = 12 in - 2*x
For the width we have a similar case:
W = 8in - 2*x
And te height of the box will be equal to x, then:
H = x
This means that the volume is:
V = (12in - 2*x)*(8 in - 2*x)*x
Here we can see the connection between the cutout and the volume of the box
Ok, this definition of f is just a bunch of points (4 to be exact).
so if point (a,b) is part of f, then f(a)=b
f(1) is about point (1,0), so f(1)=0.
g(1) = 1 (due to point (1,1))
g(2/3) = 0
f(2) = 3/4
g(-2) = 3
f(π) = -2
just a lookup once you see what is happening
Answer: You should cut out squares that are 4 inches by 4 inches.
One of the ways to do this problem is write and graph an equation. We can write an equation for the volume of this shape and then use a graphing calculator to graph it. If we look where the graph crosses 440, we will have our solution.
The volume needs to be 440. If we let x equal the side of the square that is cut out, we have the following dimensions.
Length = 19 - 2x
Width = 18 - 2x
Height = x
Volume = LWH
So our equation could be: y = (19 - 2x)(18 - 2x)x
If you graph that equation, it will intersect at the point (4, 440). Therefore, our square could be 4 by 4 inches.
