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Leni [432]
3 years ago
6

Write the percentage shown in the model

Mathematics
1 answer:
zavuch27 [327]3 years ago
3 0
1. 25
—- = 25%
100

2. 68
—— = 68%
100
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Consider a circle centered at C(-2,-4). If the point P(1,-1) lies on the circle, then which of the following points also lies on
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Answer:

Consider a circle centered at C(-2,-4). If the point P(1,-1) lies on the circle, then which of the following points also lies on the circle?

<h3>A. (-2, -√18)</h3>

B. (-2+√18, -4)

C. (√18, -4)

D. (-2, 4+√18)

Step-by-step explanation:

  • If the distance is greater than the radius, the point lies outside. If it's equal to the radius, the point lies on the circle. And if it's less than the radius, you guessed it right, the point will lie inside the circle.

hope it's help you

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A car wash detailed 198 cars in 6 hours. At what rate did the car wash detail cars in cars per
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Line AB contains points A (0, 1) and B (1, 5). The slope of line AB is
Vaselesa [24]
D.

you do change in y divided by change in x

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6 0
3 years ago
Read 2 more answers
PLEASE HELP!!!!
algol13
Sin(theta)=-15/17
cos(theta)=8/17
tan(theta)=-15/8
csc(theta)=-17/15
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4 0
3 years ago
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AB is congruent to DE because segment DE was constructed so that DE = AB. BC is congruent to EF because segment EF was construct
Alex Ar [27]

DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.

<h3>Congruent shape</h3>

Two shapes are said to be congruent if they have the same shape, all their corresponding angles and sides are congruent to one another.

Given that DE = AB and BC = EF.

In right triangle DEF, using Pythagoras:

DF² = DE² + EF²

Also, In right triangle ABC, using Pythagoras:

AC² = AB² + BC²

But DE = AB and EF = BC, hence:

AC² = DE² + EF²

AC² = DF²

Taking square root of both sides, hence:

AC = DF

Since DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.

Find out more on Congruent shape at: brainly.com/question/11329400

6 0
3 years ago
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