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pentagon [3]
1 year ago
15

NO LINKS!! Please help me with these graphs​

Mathematics
1 answer:
Stella [2.4K]1 year ago
7 0

Answer:

  • square: 9 square units
  • triangle: 24 square units

Step-by-step explanation:

Using a suitable formula the area of a polygon can be computed from the coordinates of its vertices. You want the areas of the given square and triangle.

<h3>Square</h3>

The spreadsheet in the first attachment uses a formula for the area based on the given vertices. It computes half the absolute value of the sum of products of the x-coordinate and the difference of y-coordinates of the next and previous points going around the figure.

For this figure, going to that trouble isn't needed, as a graph quickly reveals the figure to be a 3×3 square.

The area of the square is 9 square units.

<h3>Triangle</h3>

The same formula can be applied to the coordinates of the vertices of a triangle. The spreadsheet in the second attachment calculates the area of the 8×6 triangle.

The area of the triangle is 24 square units.

__

<em>Additional comment</em>

We have called the triangle an "8×6 triangle." The intention here is to note that it has a base of 8 units and a height of 6 units. Its area is half that of a rectangle with the same dimensions. These dimensions are readily observed in the graph of the vertices.

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Julli [10]

Answer:

  6 minutes

Step-by-step explanation:

'a' in the formula represents altitude in feet. You are told the altitude is 21000 feet, so put that into the formula:

   21000 = 3400t +600

You can solve this for t:

  20400 = 3400t . . . . . subtract 600 from both sides

  6 = t . . . . . . . . . . . . . . . divide both sides by 3400

The problem statement tells you that t represents minutes after lift off, so this solution means the altitude is 21000 feet 6 minutes after lift off.

The question is asking for the number of minutes after lift off that the plane reaches an altitude of 21000 feet, so this answers the question directly:

  The plane is at an altitude of 21000 feet 6 minutes after lift off.

4 0
2 years ago
The flight of a cannonball toward a hill is described by the parabola y=2+0.12x- 0.0004x^2
Stells [14]

The computation shows that the placw on the hill where the cannonball land is 3.75m.

<h3>How to illustrate the information?</h3>

To find where on the hill the cannonball lands

So 0.15x = 2 + 0.12x - 0.002x²

Taking the LHS expression to the right and rearranging we have:

-0.002x² + 0.12x -.0.15x + 2 = 0.

So we have -0.002x²- 0.03x + 2 = 0  

I'll multiply through by -1 so we have

0.002x² + 0.03x -2 = 0.

This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.

The second solution y = 0.15 * 25 = 3.75

Learn more about computations on:

brainly.com/question/4658834

#SPJ4

Complete question:

The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?

6 0
1 year ago
A student answers a multiple-choice examination question that offers four possible answers. Suppose the probability that the stu
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Answer: 0.9730

Step-by-step explanation:

Let A be the event of the answer being correct and B be the event of the knew the answer.

Given: P(A)=0.9

P(A^c)=0.1

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If it is given that the answer is correct , then the probability that he guess the answer P(B|A)= 1

By Bayes theorem , we have

P(A|B)=\dfrac{P(B|A)P(A)}{P(B|A)P(A)+P(C|A^c)P(A^c)}

=\dfrac{(1)(0.9)}{(1))(0.9)+(0.25)(0.1)}\\\\=0.972972972973\approx0.9730

Hence, the student correctly answers a question, the probability that the student really knew the correct answer is 0.9730.

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Answer: i dunno

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dexar [7]

Answer:

Slope-intercept form is

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0 = 18x + 6y – 2

First let's subtract 6y from both sides.

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y = (18 / -6)x - (2 / -6)

y = -3x + 1/3

...The last instructions are kind of confusing to me, but I think that is the answer you're after. :)

7 0
3 years ago
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