Question

Subtract. (2x^2+4x−8)−(4x^2−x+1)

Answer 1

Distribute the - to the second part of the difference:
2x^2 + 4x - 8 - 4x^ 2 + x - 1
-2x^2 + 5x - 9 

Answer 2

2x + 6 = 4x - 2
Simplifying
2x + 6 = 4x + -2

Reorder the terms:
6 + 2x = 4x + -2

Reorder the terms:
6 + 2x = -2 + 4x

Solving
6 + 2x = -2 + 4x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x' to each side of the equation.
6 + 2x + -4x = -2 + 4x + -4x

Combine like terms: 2x + -4x = -2x
6 + -2x = -2 + 4x + -4x

Combine like terms: 4x + -4x = 0
6 + -2x = -2 + 0
6 + -2x = -2

Add '-6' to each side of the equation.
6 + -6 + -2x = -2 + -6

Combine like terms: 6 + -6 = 0
0 + -2x = -2 + -6
-2x = -2 + -6

Combine like terms: -2 + -6 = -8
-2x = -8

Divide each side by '-2'.
x = 4

Simplifying
x = 4
https://www.wyzant.com/resources/lessons/math/algebra/calculators/equation?equation=2x+%2B+6+%3D+4x+-+2