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PolarNik [594]
3 years ago
7

-2/3 divided by (-1/2)

Mathematics
2 answers:
Artemon [7]3 years ago
7 0

Answer:

4/3

fillerfillerfiller

Jlenok [28]3 years ago
3 0

Answer:

1  1/3

Step-by-step explanation:

The way I learned it was to use "Keep, Change, Flip" (or KCF). It is basically "Keep" the first number (-2/3), "Flip" the sign (division symbol), and Flip the second fraction (-1/2) (switch the numerator and denominator).  Then you multiply what is left, simplify, and you are done! I hope this helped.

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Help pls ! 15−24÷4⋅2
Nady [450]

Answer:

9.28

Step-by-step explanation:

hope this help!!!

8 0
3 years ago
At best buy they have a 42" TV that sells for $1250 and is on sale 15% and sales tax is 6%.What is the final cost?
Marat540 [252]
Ok so
sale is 15% off
and add 6% tax

100-15=85
100+6=106

therefor
1250 with 15% discount plus 6% tax means
1250 times 85% times 106% =
1250 times 0.85 times 1.06=1126.25
final cost=$1126.25
4 0
3 years ago
Read 2 more answers
An older method of estimating body fat percentage was to measure a person's average density (total mass divided by total volume)
timofeeve [1]

If the density of the man is 1.0321 grams per cubic cm. Then the body fat percentage will be 28.59%.

<h3>What is a function?</h3>

The function is an expression, rule, or law that defines the relationship between one variable to another variable. Functions are ubiquitous in mathematics and are essential for formulating physical relationships.

An older method of estimating body fat percentage was to measure a person's average density (total mass divided by total volume) and apply a formula to convert it to a body fat percentage.

\rm BF = \left (\dfrac{4.57}{p} - 4.142 \right) \times 100

where BF = body fat and p = density in g/cm3 A man weighs 175 pounds.

A man weighs 175 pounds.

His total body volume is modeled by a cylinder with a height of 170 cm and a radius of 12 cm.

Then the density will be

\rm p = \dfrac{175 \times 453.592}{\pi \times 12^2 \times 170}\\\\p = \dfrac{79378.7}{76906.19}\\\\p= 1.0321 \ g/cm^3

Then the Body fat percentage will be

\rm BF = \left (\dfrac{4.57}{1.0321} - 4.142 \right) \times 100 \\\\\\BF = 0.2859 \times 100\\\\\\BF = 28.59\%

More about the function link is given below.

brainly.com/question/5245372

#SPJ1

8 0
2 years ago
If the work required to stretch a spring 2 ft beyond its natural length is 6 ft-lb, how much work is needed to stretch it 6 in.
mel-nik [20]

Answer:

0.375 feet-lb

Step-by-step explanation:

We have been given that the work required to stretch a spring 2 ft beyond its natural length is 6 ft-lb. We are asked to find the work needed to stretch the spring 6 in. beyond its natural length.

We can represent our given information as:

6=\int\limits^2_0 {F(x)} \, dx

We will use Hooke's Law to solve our given problem.

F(x)=kx

Substituting this value in our integral, we will get:

6=\int\limits^2_0 {kx} \, dx

Using power rule, we will get:

6=\left[ \frac{kx^2}{2} \right ]^2_0

6=\frac{k(2)^2}{2}-\frac{k(0)^2}{2}

6=\frac{4k}{2}-0\\\\k=3

We know that 6 inches is equal to 0.5 feet.

Work needed to stretch it beyond 6 inches beyond its natural length would be \int\limits^{0.5}_0 {kx} \, dx =\int\limits^{0.5}_0 {3x} \, dx

Using power rule, we will get:

\int\limits^{0.5}_0 {3x} \, dx = \left [\frac{3x^2}{2}\right]^{0.5}_0

\frac{3(0.5)^2}{2}-\frac{3(0)^2}{2}\Rightarrow \frac{3(0.25)}{2}-0=\frac{0.75}{2}=0.375

Therefore, 0.375 feet-lb work is needed to stretch it 6 in. beyond its natural length.

3 0
3 years ago
What is the shape of a cross section formed when a triangular prism is sliced by a plane vertical to its base?
Masteriza [31]

maybe it is supposed to be a trapezoid

5 0
4 years ago
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