What's the question being asked here?
Answer:
The slopes are

Therefore, the equations are equations of <u> Perpendicular Lines .</u>
Step-by-step explanation:
Given:
......................Equation ( 1 )
..............Equation ( 2 )
To Find:
Slope of equation 1 = ?
Slope of equation 2 = ?
Solution:
On comparing with slope point form

Where,
m = Slope
c = y-intercept
We get
Step 1.
Slope of equation 1 = m1 = 
Step 2.
Slope of equation 1 = m2 = 
Step 3.
Product of Slopes = m1 × m2 = 
Product of Slopes = m1 × m2 = -1
Which is the condition for Perpendicular Lines
The slopes are

Therefore, the equations are equations of <u> Perpendicular Lines . </u>
I have This too sooo hard
. The series is divergent. To see this, first observe that the series ∑ 1/kn for n = 1 to ∞ is divergent for any integer k ≥ 2.
Now, if we pick a large integer for k, say k > 100, then for nearly all integers n it will be true that 1 > cos(n) > 1/k. Therefore, since ∑ 1/kn is divergent, ∑ cos(n)/n must also be divergent The *summation* is divergent, but the individual terms converge to the number 0.<span>by comparison test since cosn/n <= 1/n is convergent
and 1/n is divergent by harmonic series
so the series is conditionally converget </span>