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Svetach [21]
3 years ago
12

WILL GIVE BRANLIEST PLS PLS COME LOOK!!!! PRETTY PLS WITH SPRINKLES ON TOP!!!

Mathematics
2 answers:
Elena-2011 [213]3 years ago
5 0
The answer is a on the question
anzhelika [568]3 years ago
4 0

Answer: A

Step-by-step explanation:

You might be interested in
Picture is attached. help
Svetradugi [14.3K]
True. Polynomial means consisting of several terms. A<span>n expression of more than two algebraic terms, especially the sum of several terms that contain different powers of the same variables. 
For example:
f(x) = x3 + 2x 1/2

Since there are two parts to this equation, it is polynomial.
I hope I helped.</span>
8 0
3 years ago
- 3(3s - 4) - 12 = - 3/6s + 1) - 4
s344n2d4d5 [400]

Answer:

s=-7/9

Step-by-step explanation:

-9s+12-12=-18s-3-4

-9s=-18s-7

9s=-7

s=-7/9

(if I understood the question correctly)

6 0
3 years ago
Mick departs Sydney on Tuesday at 6:00 am and arrives in Christchurch on Tuesday at 12:45 pm. If Christchurch time is 2 hours ah
Andrej [43]

Answer:

4 hours and 45 minutes.

Step-by-step explanation:

Since Christchurch is 2 hours ahead of Sydney, you subtract 2 from 12:45 and get 10:45 so then, you determine the difference between 10:45 and 6:00 AM and it results in 4.75 hours or 4 hours and 45 minutes

7 0
3 years ago
I will give the brainiest
Dominik [7]
The price of the ticket would be 9dollars
3 0
3 years ago
Simplified radical form of 4800 feet how many seconds was the diver in a free fall? Using functions (t)=16t^2 models the distanc
amm1812

Answer:

The diver will be in free fall for 10\sqrt{3} seconds.

Step-by-step explanation:

The distance in feet, that an object falls in t seconds is given by the function h(t) = 16t^{2}.

Now, given that the height is 4800 feet and we have to calculate the number of seconds the diver was in a free fall.

Therefore, 4800 = 16t^{2}

⇒ t^{2} = \frac{4800}{16} = 300

⇒ t = \sqrt{300} = \sqrt{100 \times 3} = 10\sqrt{3} seconds.

Therefore, the diver will be in free fall for 10\sqrt{3} seconds. (Answer)

5 0
3 years ago
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