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borishaifa [10]
3 years ago
7

Which values are solutions to x 5

Mathematics
1 answer:
vredina [299]3 years ago
6 0
Um this question is unclear
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Follow me on inst.a sarinagaytan123
kati45 [8]

ok Step-by-step explanation:

5 0
3 years ago
Does anyone get this question plss
a_sh-v [17]

Answer:

D)  1.0

Step-by-step explanation:

if y = 1 then x = 1

6 0
3 years ago
What is the interquartile range of this data 0 5 10 15 20​
timama [110]
The interquartile range (IQR) is 15.

To find the IQR, you must:
1) Find the median
2) Split the data set in two at the median.
3) Find the medians from both the groups you made in Step 2
4) Label the smaller one Quartile 1 and the larger one Quartile 3 (Hint: The median is Quartile 2)
5) Subtract: Quartile 3 - Quartile 1
5 0
3 years ago
Suppose we want to see if American children have higher levels of cholesterol than the average child (i.e., in the entire world
lina2011 [118]

Answer:

t=\frac{201-190}{\frac{10}{\sqrt{25}}}=5.5    

p_v =P(t_{(24)}>5.5)=0.00000589  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the true mean is higher than 190

Step-by-step explanation:

Data given and notation  

\bar X=201 represent the mean

s=10 represent the sample standard deviation for the sample  

n=25 sample size  

\mu_o =190 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 190, the system of hypothesis would be:  

Null hypothesis:\mu \leq 190  

Alternative hypothesis:\mu > 190  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{201-190}{\frac{10}{\sqrt{25}}}=5.5    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=25-1=24  

Since is a one side test the p value would be:  

p_v =P(t_{(24)}>5.5)=0.00000589  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the true mean is higher than 190

3 0
3 years ago
Question 3 (1 point)
Rom4ik [11]

Answer:

y = 3x - 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 3 , then

y = 3x + c ← is the partial equation

To find c substitute (2, 3) into the partial equation

3 = 6 + c ⇒ c = 3 - 6 = - 3

y = 3x - 3 ← equation of line

6 0
3 years ago
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