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Serggg [28]
2 years ago
6

The table shows the home state of the 175 high school students who attended a tri-state debate tournament. The ratio of Illinois

students to Michigan students was 6 : 5. How many students were from Michigan? Indiana?
Mathematics
2 answers:
Bess [88]2 years ago
8 0

If you can provide me with the table, where it gives you all your information for this question, I can edit this and show you how to do it. (with answer). It's hard to answer something where you don't know what you need to answer.

UNO [17]2 years ago
4 0

the answer is 70.

hope this helps

:)

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Find the equation of the line through (6,4) and (-3,-8)
alexdok [17]

Answer:

y = 4/3x - 4

Step-by-step explanation:

to find the equation of a line with 2 points, we use the slope formula which is:

\frac{y_2-y_1}{x_2-x_1}

we will use (6,4) as x_1[tex] and [tex]y_1 and we will use (-3,-8) as x_2[tex] and [tex]y_2. we plug this into the slope formula:

\frac{-8-4}{-3-6}

-8 - 4 = -12

-3 - 6 = -9

the slope is \frac{-12}{-9}

but we can simplify this further by dividing the fraction by -3

-12 / -3 = 4

-9 / -3 = 3

the simplified version of the slope is \frac{4}{3}

we can write this in slope-intercept form which is y =mx + b, with b being the y intercept and m being the slope

y = 4/3x + b <--- we need to solve for <em>b</em> in order to find the y intercept, so substitute x & y for a point on the line, we can use any point we are given, but for this example i will use (6,4)

4 = 4/3(6) + b < multiply 4/3 x 6

4 = 8 + b < subtract 8 from both sides

-4 = b

our y intercept would be (0,-4)

the equation looks like the following:

y = 4/3x - 4, which is our answer

3 0
3 years ago
HELP HELP HELP<br> HELP HELP <br> HELP <br> (STEP BY STEP)
Marizza181 [45]

With some simple rearrangement, we can rewrite the numerator as

2x^3 - 3x^2 - x + 4 = 2(x^3 - x) - 3x^2 + x + 4 \\\\ ~~~~~~~~ = 2x(x^2-1) - 3(x^2 - 1) + x + 1 \\\\ ~~~~~~~~ = (2x-3)(x^2-1) + x+1

Then factorizing the difference of squares, x^2-1=(x-1)(x+1), we end up with

\dfrac{2x^3 - 3x^2 - x + 4}{x^2 - 1} = \dfrac{(2x-3)(x-1)(x+1) + x+1}{(x-1)(x+1)} \\\\ ~~~~~~~~ = \boxed{2x-3 + \dfrac1{x-1}}

3 0
2 years ago
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