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3 years ago

-6x-6×-6x-6×-10x-2×-10x-2

Mathematics

1 answer:

katovenus [111]3 years ago

3 0

The correct answer is 518,400

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2. For the three-part question that follows, provide your answer to each part in the given

FrozenT [24]

Answer:

Step-by-step explanation:

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3 years ago

What is the radius of a sphere whose surface area is 100 square centimeters?

professor190 [17]

Answer:

Step-by-step explanation:

The formula for determining the surface area of a sphere is expressed as

Surface area = 4πr^2

Where

r represents the radius of the sphere

π is a constant whose value is 3.14

From the information given,

Surface area of the sphere = 100 centimeters ^2. Therefore,

100 = 4 × 3.14 × r^2

100 = 12.65r^2

r^2 = 100/12.65 = 7.9051

r = √7.9051

r = 2.81 centimeters

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3 years ago

What is Z for the equation 1/2 z=-3/4+1/4z −3 −1 1 3

dolphi86 [110]

1)
multiply all by the least common multiply:

$(\frac{1}{2} ) \times 4 = 2$

$( - \frac{3}{4} ) \times 4 = - 3$

$( \frac{1}{4} ) \times 4 = 1$
$+ 1z = - 3$
$z = \frac{ - 3}{1}$
$z = - 3$

6 0

4 years ago

Use the fraction strips to answer. Choose the sign that goes between the two fractions.

mariarad [96]

Answer: B

Step-by-step explanation: 2/3 is bigger than 2/4

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3 years ago

1. Bob tried to answer the following question by finding the missing angle and rounding the answer to the nearest degree.

iren2701 [21]

Answer:

Part 1)

Bob's mistake was to have used the cosine instead of the sine

The measure of the missing angle is $53.13\°$

Part 2) The surface area of the pyramid is $288\ cm^{2}$

Step-by-step explanation:

Part 1)

Let

x----> the missing angle

we know that

In the right triangle o the figure

The sine of angle x is equal to divide the opposite side angle x to the hypotenuse of the right triangle

$sin(x)=\frac{16}{20}$

$x=arcsin(\frac{16}{20})=53.13\°$

Bob's mistake was to have used the cosine instead of the sine

Part 2) we know that

The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces

$SA=b^{2}+4[\frac{1}{2}(b)(h)]$

where

b is the length side of the square

h is the height of the triangular lateral face

In this problem

$h=b/2$ -------> by an 45° angle

$b=2h$

$sin(45\°)=\frac{h}{6\sqrt{2}}$

$h=6\sqrt{2}(sin(45\°))=6\ cm$

Find the value of b

$b=2(6)=12\ cm$

Find the surface area

$SA=12^{2}+4[\frac{1}{2}(12)(6)]=288\ cm^{2}$

3 0

4 years ago