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3 years ago

What is the length of BC? Please include how you got it :)

Mathematics

2 answers:

Crank3 years ago

6 0

Answer:

BC = 24

Step-by-step explanation:

We know that triangles CAB and CED are similar because all three of their angles are the same. Thus, we know that the side lengths of these triangles have to be proportional to each other. You would match side BC with side DC and sides AC with EC.

AC/EC = BC/DC

30/10 = (32-x)/x

3 = (32-x)/x

Then using algebraic properties, solve for x.

3x = 32 - x

4x = 32

x = 8.

Lastly, plug in 8 for the x in BC, 32 - 8, so the length of BC is 24

Mrrafil [7]3 years ago

3 0

Answer:

Step-by-step explanation:

Δ CBA and Δ CDE are similar triangles, then the ratios of corresponding sides are equal, that is

$\frac{CB}{CD}$ = $\frac{CA}{CE}$ , substitute values

$\frac{32-x}{x}$ = $\frac{30}{10}$ = 3 ( multiply both sides by x )

32 - x = 3x ( add x to both sides )

32 = 4x ( divide both sides by 4 )

8 = x

Then

BC = 32 - x = 32 - 8 = 24 → B

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dion places a ladder against The side of his house as shown in the diagram below. Dion’s water is 26 feet long, and he places th

gregori [183]

Complete question :

dion places a ladder against The side of his house as shown in the diagram below. Dion’s water is 26 feet long, and he places the ladder at a 70° angle with the ground, How high does the ladder reach up the side of the building?.

Answer:

24.43 feets

Step-by-step explanation:

Using trigonometry :

Sinθ = opposite / hypotenus

Opposite = height, h

Hypotenus = 26

Sin 70° = h / 26

0.9396926 * 26 = h

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6 0

3 years ago

(6ab-8a+8) - (7ab-1 )

PSYCHO15rus [73]

Answer:

$- ab - 8a + 9$

Step-by-step explanation:

$(6ab - 8a + 8) - (7ab - 1) \\ 6ab - 8a + 8 - 7ab + 1 \\ - ab - 8a + 9$

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4 0

3 years ago

Read 2 more answers

Given: KL ║ NM , LM = 45, m∠M = 50° KN ⊥ NM , NL ⊥ LM Find: KN and KL

Mice21 [21]

Answer:

$KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08\\ \\KN=45\sin 50^{\circ}\approx 34.47$

Step-by-step explanation:

Given:

KL ║ NM ,

LM = 45

m∠M = 50°

KN ⊥ NM

NL ⊥ LM

Find: KN and KL

1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,

LM = 45

m∠M = 50°

So,

$\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}$

Also

$m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ}$ (angles LNM and M are complementary).

2. Consider triangle NKL. This is a right triangle, because KN ⊥ NM . In this triangle,

$NL=45\tan 50^{\circ}$

$m\angle KLN=m\angle LNM=40^{\circ}$ (alternate interior angles)

$m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ}$ (angles KNL and KLN are complementary).

So,

$\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08$

and

$\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47$