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2 years ago

Find the value of X help asap plz

Mathematics

2 answers:

timama [110]2 years ago

4 0

Answer:

12!! Glad I could help!!

telo118 [61]2 years ago

3 0

Answer:

D) 12

Step-by-step explanation:

I would say that this is 12 because the angle x looks the same as the other shown angle.

Hope it helps!

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Amy’s age plus Betty’s age is 29 years. Amy’s plus Carl’s age is 27 years. Betty’s plus Carl’s age is 22 years. What is the diff

eduard

Answer: 12

Step-by-step explanation

4 0

2 years ago

Tell wether the angles are adjacent or vertical. Then find the value of x.

Gre4nikov [31]

Answer:

The angles are vertical

Step-by-step explanation:

x+42+2x+1=180

put the like terms together i.e 2x+x+42+1=180

you get: 3x+43=180

Take 43 to th other side of 180 i.e 3x=180-43 i.e (180-43=137)

You get 3x=137

Divide both sides by 3

you get x=45.666666666667(Round off to get 45.67)

Substitute the value of x to the angles

x+42(45.67+42=87.67)

2x+1(2(45.67)+1=92.34

Add 87.67+92.34=180

THis shows that the angles are vertical

8 0

2 years ago

Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.

WINSTONCH [101]

Answer:

a) $y(t) = y_{0}e^{4t} + 2$ . It does not have a steady state

b) $y(t) = y_{0}e^{-4t} + 2$ . It has a steady state.

Step-by-step explanation:

a) $y' -4y = -8$

The first step is finding $y_{n}(t)$ . So:

$y' - 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r - 4 = 0$

$r = 4$

So:

$y_{n}(t) = y_{0}e^{4t}$

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' -4(y_{p}) = -8$

$(C)' - 4C = -8$

C is a constant, so (C)' = 0.

$-4C = -8$

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{4t} + 2$

b) $y' +4y = 8$

The first step is finding $y_{n}(t)$ . So:

$y' + 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r + 4 =$

$r = -4$

So:

$y_{n}(t) = y_{0}e^{-4t}$

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' +4(y_{p}) = 8$

$(C)' + 4C = 8$

C is a constant, so (C)' = 0.

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{-4t} + 2$

6 0

3 years ago

How would u write three times a number x

Law Incorporation [45]

Can write 3x or 3(x) or 3•x

7 0

2 years ago

Read 2 more answers

Divide using Synthetic Division<br> 2. x3 - 4x² + 2x +5<br> X-2

jok3333 [9.3K]

Answer:

the answer is 9

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers