Question

Which box shows a relationship where the constant of proportionality is 64?

Answer 1

Answer:

C

Step-by-step explanation:

Constant of proportionality = $\frac{y}{x}$

Let's find out which if the boxes will give us 64 as constant of proportionality.

A. $\frac{y}{x} = \frac{11}{2} = 5.5$ ≠ 64

B. $\frac{y}{x} = \frac{5}{15} = \frac{1}{3}$ ≠ 64

C. $\frac{y}{x} = \frac{16}{\frac{1}{4}} = 16*\frac{4}{1} = 64$ ≠ 64

D. $\frac{y}{x} = \frac{\frac{3}{7}}{3} = \frac{3}{7}*\frac{1}{3} = \frac{1}{7}$ ≠ 64

E. $\frac{y}{x} = \frac{2}{-10} = -\frac{1}{5}$ ≠ 64

F. $\frac{y}{x} = \frac{21}{6} = \frac{7}{2}$ ≠ 64

G. $\frac{y}{x} = \frac{4}{8} = \frac{1}{2}$ ≠ 64

From the boxes given, box C is the only box that shows us a relationship where the constant of proportionality is 64.