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lapo4ka [179]
3 years ago
13

The equation f = v + at represents the final velocity of an object, f, with an initial velocity, v, and an acceleration rate, a,

over time, t.
Which is an equivalent equation solved for t?
Mathematics
1 answer:
Elenna [48]3 years ago
4 0

Answer:

(f-v)/a = t

Step-by-step explanation:

f = v + at

Subtract v from each side

f-v = v-v + at

f-v = at

Divide each side by a

(f-v)/a = at/a

(f-v)/a = t

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4 years ago
8/11 written as a decimal
svlad2 [7]

Answer:

0.72727272727 or 0.73

Step-by-step explanation:

To get that all you have to do is divide 8 by 11. So 8 divided by 11 equals 0.72727272727 which would round up to 0.73

5 0
4 years ago
The braking distance, in feet of a car a Travling at v miles per hour is given.
irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

  • The braking distance at 25 mph, is approximately <u>63.7 ft.</u>
  • The braking distance at 55 mph,  is approximately <u>298.35 ft.</u>
  • The braking distance at 85 mph,  is approximately <u>708.92 ft.</u>

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.

At 25 mph, the braking distance is approximately <u>63.7 ft.</u>

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945  ft.s

D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.

At 55 mph, the braking distance is approximately <u>298.35 ft.</u>

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.

At 85 mph, the braking distance is approximately <u>708.92 ft.</u>

b. The speed of the car when the braking distance is 450 feet is given as follows;

450 = 2.6 + \dfrac{v^2}{22}

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ <u>98.211 ft./s</u>

Learn more here:

brainly.com/question/18591940

8 0
2 years ago
What would the y intercept of a line B if it is perpendicular to 1/3x+2
Thepotemich [5.8K]

Hey!

Hope this Helps....

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

To find the perpendicular line, of any given line goes like this...

if m (slope) of this given line is 1/3, than we know that the perpendicular line has a slope of -3

Now, to find the equation of this line, we need to find out where it crosses the y-axis... And because we are not given any specific points on where the perpendicular line crosses. We see that the point it pass the y-axis is 0

So... the perpendicular line of 1/3x+2 is -3x

7 0
4 years ago
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