Answer:
a. $1669
Step-by-step explanation:
Price in 1994 = [ (CPI in 1994) / (CPI 1973) ] * (Price in 1973) =
[ 148.2 / 44.4 ] * 500 = 1668.91891892 = $1669 rounded to the nearest dollar.
Answer:
it would move 4 in the negative direction
Answer:
probability at least one zero is 0.3439
Step-by-step explanation:
given data
last four digits = randomly selected
to find out
probability that for one such phone number the last four digits include at least one 0.
solution
we know there are total 10 digit
so we first find probability of non zero digit i.e.
Probability ( non zero ) = 9 /10 = 0.9
and now we find probability of none of digit zero only event happen n= 4 time in a row by multiplication rules i.e
Probability ( none zero in 4 digit ) = ![0.9^{n}](https://tex.z-dn.net/?f=0.9%5E%7Bn%7D)
Probability ( none zero in 4 digit ) = ![0.9^{4}](https://tex.z-dn.net/?f=0.9%5E%7B4%7D)
Probability ( none zero in 4 digit ) = 0.6561
so we can say probability at least one zero = 1 - Probability ( none zero in 4 digit )
probability at least one zero = 1 - 0.6561
probability at least one zero is 0.3439
Solving a system of equations, we will see that there are 6000 kg of coal on the pile.
<h3>
How many kilograms of coal are in the pile of coal?</h3>
Let's say that there are N kilograms of coal, and it is planned to burn it totally in D days, these are our variables.
We know that:
- If the factory burns 1500 kilograms per day, it will finish burning the coal one day ahead of planned.
- If it burns 1000 kilograms per day, it will take an additional day than planned.
Then we can write the system of equations:
(1500)*(D - 1) = N
(1000)*(D + 1) = N
Because N is already isolated in both sides, we can write this as:
(1500)*(D - 1) = N = (1000)*(D + 1)
Then we can solve for D:
(1500)*(D - 1) = (1000)*(D + 1)
1500*D - 1500 = 1000*D + 1000
500*D = 2500
D = 2500/500 = 5
Now that we know the value of D, we can find N by replacing it in one of the two equations:
(1500)*(D - 1) = N
(1500)*(5 - 1) = N
(1500)*4= N = 6000
This means that there are 6000 kilograms of coal on the pile.
If you want to learn more about systems of equations:
brainly.com/question/13729904
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