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lara [203]
2 years ago
8

How much would $200 invested at 7% interest compounded annually be worth after 5 years? Round your answer to the nearest cent. D

o not include units in your answer
Mathematics
2 answers:
stiv31 [10]2 years ago
7 0

Answer:

Compounded amount after 5 years (A) = $280.51

Step-by-step explanation:

Given: P = $200, r = 7% = 7/100 = 0.07, n = 5 years

Compounded amount after 5 years (A) = P(1 +r)^n

Now plug in the given values in the above formula, we get

A = 200(1 + 0.07)^5

A = 200*(1.07)^5

A = 200 *1.4025517307

A = $280.51

Compounded amount after 5 years (A) = $280.51

Hope this will helpful.

Thank you.

viktelen [127]2 years ago
6 0
The future worth (F) of the investment at present (P) with a compound interest i after n years is calculated through the equation,
                                      F = P x (1 + i)^n
Substituting the known values,
                                      F = ($200) x (1 + 0.07)^5 = $280.51
Thus, the future worth of the investment is approximately $280.51. 
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See Below.

Step-by-step explanation:

We are given the graph of <em>y</em> = f'(x) and we want to determine the characteristics of f(x).

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Hence, <em>f</em> is increasing for the interval:

(-\infty, -2) \cup (-1, 1)\cup (3, \infty)

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\displaystyle (-2, -1) \cup (1, 3)

Part B)

<em>f</em> has a relative maximum at <em>x</em> = <em>c</em> if <em>f'</em> turns from positive to negative at <em>c</em> and a relative minimum if <em>f'</em> turns from negative to positive to negative at <em>c</em>.

<em>f'</em> turns from positive to negative at <em>x</em> = -2 and <em>x</em> = 1.

And <em>f'</em> turns from negative to positive at <em>x</em> = -1 and <em>x</em> = 3.

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Part C)

<em>f</em> is concave up whenever <em>f''</em> is positive and concave down whenever <em>f''</em> is negative.

In other words, <em>f</em> is concave up whenever <em>f'</em> is increasing and concave down whenever <em>f'</em> is decreasing.

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Part D)

Points of inflections are where the concavity changes: that is, <em>f''</em> changes from either positive to negative or negative to positive.

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<em>f'</em> has extrema at (approximately) <em>x</em> = -1.5, 0, and 2.2.

Hence, <em>f</em> has inflection points at <em>x</em> = -1.5, 0, and 2.2.

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