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lawyer [7]
3 years ago
10

Suppose that the first team member in a 3-person relay race must run 2 1/4 laps, the second team member must run 1 1/2 laps, and

the third team member must run 3 5/8 laps. How many laps in all must each team run?
Mathematics
2 answers:
Kisachek [45]3 years ago
6 0

You need to add up all 3 mixed numbers to find the total laps.

2 + 1/4 + 1 + 1/2 + 3 + 5/8 =

(2 + 1 + 3) + (1/4 + 1/2 + 5/8) =

6 + (2/8 + 4/8 + 5/8) =

6 + (11/8) =

6 + (1 + 3/8) =

7 3/8 laps


stich3 [128]3 years ago
5 0

Answer: There are 7\dfrac{3}{8} laps in all.

Step-by-step explanation:

Since we have given that

Number of laps must run by first team = 2\dfrac{1}{4}=\dfrac{9}{4}

Number of laps must run by second team = 1\dfrac{1}{2}=\dfrac{3}{2}

Number of laps must run by third team = 3\dfrac{5}{8}=\dfrac{29}{8}

So, total number of laps in all must run is given by

\dfrac{9}{4}+\dfrac{3}{2}+\dfrac{29}{8}\\\\=\dfrac{18+12+29}{8}\\\\=\dfrac{59}{8}\\\\=7\dfrac{3}{8}

Hence, there are 7\dfrac{3}{8} laps in all.

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Write an equation of the perpendicular bisector of the segment with endpoints G 9,8       and H 3,2      .
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Answer:

y = -x + 11

Step-by-step explanation:

The equation of a straight line is is given by:

y = mx + b; where m is the slope and b is the y intercept

The equation of the line joining G(9, 8) and H(3, 2) is given as:

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-8=\frac{2-8}{3-9}(x-9)\\\\y-8=x-9\\\\y=x-1

The perpendicular bisector of the line joining G(9, 8) and H(3, 2) is perpendicular to the line joining G(9, 8) and H(3, 2) and passes through the midpoint of line joining G(9, 8) and H(3, 2).

Let (x, y) be the midpoint of the line joining G(9, 8) and H(3, 2). Hence:

x = (9 + 3)/2 = 6

y = (8 + 2)/2 = 5

The midpoint = (6, 5)

Two lines are perpendicular if the product of their slopes is -1.

The line joining G(9, 8) and H(3, 2) has a slope of 1, hence, the slope of the perpendicular bisector would be -1.

This means that the perpendicular bisector has a slope of -1 and passes through (6, 5). Using:

y-y_1=m(x-x_1)\\\\y-5=-1(x-6)\\\\y-5=-x+6\\\\y=-x+11

The equation of the perpendicular bisector is y = -x + 11

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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Find points from graph.</em>

Point (2, -1)

Point (-4, -3)

<u>Step 2: Find slope </u><em><u>m</u></em>

Simply plug in the 2 coordinates into the slope formula to find slope <em>m</em>

  1. Substitute [SF]:                     m=\frac{-3+1}{-4-2}
  2. Add/Subtract:                       m=\frac{-2}{-6}
  3. Simplify:                                m=\frac{1}{3}
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