Answer:
7.878 ft far
Step-by-step explanation:
Given:
- A ramp is to be lifted to an angle Q = 10 degrees
- The total length of the ramp L = 8 ft
Find:
- how far does the ramp need to be away to hit the edge of the step
Solution:
- The question asks in "other words" the horizontal distance (d) from the ramp pivot on the floor to the edge of the step when it is lifted 10 degrees.
- We will use trigonometry to solve a right angle triangle: The horizontal distance is a projection of Length L on to the flat ground surface. Hence, we have:
cos(Q) = d / L
d = L*cos(Q)
- Plug in values:
d = 8*cos(10)
Answer: d = 7.878 ft
Answer: there is no picture for this question
Step-by-step explanation:
m<SMJ + m<SME = 180° <em>(Linear pair) ⇒ </em>m<SMJ + 59° = 180° ⇒ m<SMJ = 121°
m<MJS ≅ m<EJA: <E + <A + <J = 180° ⇒ 90° + 48° + <J = 180° ⇒ <J = 42°
<u>m<JSM + m<SMJ + m<MJS = 180° </u><u><em> (Triangle sum) </em></u>
m<JSM + 121° + 42° = 180°
m<JSM + 163° = 180°
m<JSM = 17°
Answer: 17°
The rectangle was basically cut into two right angles so all you have to find is the length of the triangle. Using what we know which is the h<span>ypotenuse and the height, use the equation x= the square root of c^2 - a^2.
The base is x = 9.17 in</span>
Answer:
2.25 or 2 1/4 pounds
Step-by-step explanation:
if you add them all up (I converted them to decimals when adding) you get 13.5 or 13 1/2 if your using fractions, then you divide that by 6 because thats how many jars there are and you get 2.25 or 2 1/4
