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aivan3 [116]
2 years ago
15

The graph of y= -2 + 10 is:

Mathematics
1 answer:
Anestetic [448]2 years ago
3 0

Answer:

Step-by-step explanation:

+ The graph of a function like y= ax + b with a, b reals is always a line.

This line contains all of solution of this equation with 2 variable ax -y +b=0.

+ So the answer is D.\

Hope you understand it.

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Here is a system of equations.
goblinko [34]

Answer:

It should be "one solution"

Step-by-step explanation:

After graphing the equations, the two lines only intersect at one point which makes it "one solution." Hope this helps.

8 0
2 years ago
Read 2 more answers
im so confused and I'm ready to just throw my computer at the wall, how do you graph 3/5x + 9? i get the graphing the y intercep
Hunter-Best [27]

Answer:

start by placing a point on 9

Step-by-step explanation:

then use "rise over run" ( which is ri/ru) so you go up 3, then over 5. (hope this helps!)

8 0
3 years ago
Question is in the picture<br>please help
LiRa [457]

When given the graph of a function, the domain would include all the points that there is a graph. The strategy is to find what <em>is not</em> included.

What we are looking for are points of discontinuity. Think of it as when you remove your pencil from the paper.

From left to right, the graph stops at x = -3. So anything less than -3 is in the domain. Next, the graph starts up again at x =-1 after an asymptote (the vertical dashed lines). This piece goes to x = 4. So our domain is from -1 to 4.

Lastly, there's a jump from 4 to 5 and the graph goes on again. After 5, we take all the stuff more than it. So x > 5 is in the domain.

So x < -3, - 1 < x < 4, and x > 5 appears to be our domain. However, end points needed to be checked to see if we include them or not. Again we go left to right.

At x = -3 there is a filled (or closed) circle and that means we include -3.

At x = -1 there is an asymptote. Asymptotes are things you get close to but don't get to. (Think of it as the "I'm Not Touching" game you play on car trips.) So we exclude -1.

At x = 4 there is an unfilled (or open) circle and that means we exclude 4.

At x = 5 there is a filled circle so we include 5.

Now we refine our domain for the endpoints.

x ≤ -3, -1 < x < 4, x ≥ 5 is our domain.

The problem gives us intervals, and we gave it in inequalities. When we include an endpoint we use brackets - [ and } and when we exclude and endpoint we use parentheses - ( and ). Let's go back to x ≤ -3. Anything less works, and -3 is included (closed circle). That interval is (-∞, -3]. Next is the piece between -1 and 4. Since both are excluded, (-1,4) is our interval. We include 5 to write x ≥5 as the interval [5,∞).

Put the bolded ones all together and use the union, ∪, symbol to connect them, since something on the graph could be in any piece.

Our domain is (-∞, -3] ∪(-1,4) ∪ [5,∞).

5 0
3 years ago
Y = -x+5y=−x+5y, equals, minus, x, plus, 5
Serga [27]
The answer is D
Hope this hel
6 0
2 years ago
Multiply four and eight tenths multiplied by three.
Romashka [77]
Fourteen and four tenths
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