Answer:
The answer is 14.5
Step-by-step explanation:
THE ANSWER IS B! YOUR WELCOME!
Answer:
c≥2(x-2) ÷ 5
Step-by-step explanation:
5c+3≥6x-8
5c ≥6x-8-3
5c≥6x-12
c≥(6x-12) ÷ 5
c≥ 2(x-2) ÷5
3.010101.. = 3 + 0.010101... = 3 + 1/(100 - 1) = 3 + 1/99 = 3 1/99
You can write 2311 and 3912 in the form
:


Then


Taken modulo 20, the terms containing powers of 20 vanish and you're left with

We further have

so we end up with

and so
.
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If instead you're trying to find
, you can apply Euler's theorem. We can show that
using the Euclidean algorithm. Then since
, and 8 divides 3912, we have

To show 2311 and 20 are coprime:
2311 = 115*20 + 11
20 = 1*11 + 9
11 = 1*9 + 2
9 = 4*2 + 1 => gcd(2311, 20) = 1