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Anna35 [415]
2 years ago
11

Simplify 2^3/7 • 2^1/4

Mathematics
1 answer:
poizon [28]2 years ago
7 0

Answer:

4/7Hope this helps :)

Step-by-step explanation:

Exact form:4/7

Decimal form:0.571428

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First find f′ and then find f. f′′(x)=3x^3+6x^2−x+2, f′(1)=9, f(1)=−7. <br> f′(x)= <br> f(x)=
Vadim26 [7]
I haven't learned antiderivitives yet but I can try to logic it

<span>First find f′ and then find f. f′′(x)=3x^3+6x^2−x+2, f′(1)=9, f(1)=−7.

we reverse chain rule

3x^3, we know that it was a 4th degree thing, and the coefient is 3, so
4*what=3?, answer is 3/4
3/4x^4

6x^2
we know it was x^3, and the coefient is now 6 so
3*what=6? what=2
2x^3

-1x, the power was 2 and coefient is now -1, so
2 times what=-1?, -1/2
-1/2x^2

2, that is from 2x

so
</span>
<span>3/4x^4+2x^3-1/2x^2+2x=f'(x)
test x=1
(3/4)(1)+2(1)-(1/2)(1)+2(1)=
3/4+2-2/4+2=
4 and 1/4 we need to get it to 9
4 and 1/4 +what=9
answer is 4 and 3/4
so we add that to the end since it will become 0 from derivitive

</span>
<span>f'(x)=3/4x^4+2x^3-1/2x^2+2x+4 and 3/4

now reverse drivitive again

3/4x^4
exponent is 5 and coefient is 3/4
5 times what=3/4? answer is 3/20
3/20x^5

2x^3
exponent should be 4 and coefient is 2
4 times what=2? answer is 1/2
1/2x^4

-1/2x^2
exponent should be 3 and coefient is -1/2
3 times what=-1/2? answer is -1/6
-1/6x^3

2x
exponent should be 2 and coefient is 2
2 times what=2? answer is 1
1x^2

4 and 3/4 turns to (4 and 3/4)x



</span>
<span>f(x)=3/20x^5+1/2x^4-1/6x^3+x^2+(4 and 3/4)x
try evaluating it for x=1
f(1)=(3/20)+(10/20)-(10/50)+1+(19/4)
f(1)=6 and 7/30
what do we add to get -7
-13 and 7/30
</span>
<span><span>f(x)=3/20x^5+1/2x^4-1/6x^3+x^2+(4 and 3/4)x-13 and 7/30

</span>


</span>ANSWER
<span>f'(x)=3/4x^4+2x^3-1/2x^2+2x+19/4
</span><span>f(x)=3/20x^5+1/2x^4-1/6x^3+x^2+19/4x-187/30</span>
4 0
3 years ago
Let the sequence {an} be defined so that a1 = 1 and each succeeding term is found by adding 3 to the one before it. Find the for
Sauron [17]

Answer:

C

Step-by-step explanation:

The sequence is arithmetic with n th term

a_n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 1 and d = 3, thus

a_{n} = 1 + 3(n - 1) = 1 + 3n - 3 = 3n - 2 → C

6 0
3 years ago
HELPPPPP ITS URGENTTTTT<br><br> click on the photo
ArbitrLikvidat [17]

Answer:

x=67.4

Step-by-step explanation:

well sin30:1/2

So y is not 30 since 5/13 doesn’t equal 1/2

So it’s either the the third or fourth option

And x>y

So option 4 is correct

7 0
1 year ago
Let X be the number of Heads in 10 fair coin tosses. (a) Find the conditional PMF of X, given that the first two tosses both lan
inn [45]

Answer:

Follows are the solution to the given point:

Step-by-step explanation:

For option A:

In the first point let z be the number of heads which is available on the first two trails of tosses so, the equation is:

P(X=k | z=2 ) = \begin{pmatrix} 10-2\\ k-2\end{pmatrix} (\frac{1}{2})^{k-2} (\frac{1}{2})^{10-k}

                         = \begin{pmatrix} 8\\k-2\end{pmatrix} (\frac{1}{2})^{k-2} (\frac{1}{2})^{10-k} \ \ \ \ \ \ \ \ \  \ \\\\

                                                                                                       k= 2,3..........10For option B:

P(X=k | X \geq 2 ) =  \sum^{10}_{i=2}  \begin{pmatrix} 10-i\\ k-i\end{pmatrix} (\frac{1}{2})^{k-i} (\frac{1}{2})^{10-k}

                                                                                                k= 2,3, 4.........10

8 0
3 years ago
How can help me with (c)
dimulka [17.4K]
X^2-y^3=6
x^2-6=y^3
y= (x^2-6)^1 by 3
6 0
3 years ago
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