Point A has an x-coordinate of 7 and lies below the x-axis on a circle with a center at (0, 0) and a radius of 8.

Lisa Richter deposited $5,000 at 4% compounded semiannually for three years. At the beginning of the fourth year, Lisa deposited

Jet001 [13]

I suppose it is the fourth one I'm sorry if I'm wrong

3 0

3 years ago

3x + 6x^2 Is this a third-degree polynomial in standard form?

rjkz [21]

No. For it to be in standard form the term with the largest exponent comes first. Standard form would be 6x^2-3x. It is a second degree polynomial because 6x is raised to the 2nd power. It would be a third degree polynomial if the largest degree was raised to the 3rd power.

6 0

3 years ago

In a group of 31 students, 7 study both Art and Biology.

ale4655 [162]

Answer:

it is 358

Step-by-step explanation:

Hope this helped have an amazing day!

7 0

3 years ago

Find the distance from point A(−1, 7) to the line y=3x. Round your answer to the nearest tenth.

bearhunter [10]

Answer:

The distance from the point to the line is approximately 3.2 units

Step-by-step explanation:

Distance From a Point to a Line

Is the shortest distance from a given point to any point on an infinite straight line. The shortest distance occurs when the segment from the point and the line are perpendiculars.

If the line is given by the equation ax + by + c = 0, where a, b and c are real constants, the distance from the line to a point (x0,y0) is

$\displaystyle d= \frac{|ax_0+by_0+c|}{\sqrt{a^2+b^2}}$

The line is given by the equation:

y=3x. We need to transform it into the specified form.

Subtracting 3x:

y - 3x = 0

Comparing with the general form of the line, we have

a=-3, b=1, c=0

The point (xo,yo) is (-1,7), thus:

$\displaystyle d= \frac{|-3\cdot (-1)+1\cdot 7+0|}{\sqrt{(-3)^2+1^2}}$

$\displaystyle d= \frac{|3+7|}{\sqrt{9+1}}$

$\displaystyle d= \frac{|10|}{\sqrt{10}}$

$\displaystyle d= \frac{10}{\sqrt{10}}$

$d\approx 3.2$

The distance from the point to the line is approximately 3.2 units

4 0

3 years ago

A ball is thrown into the air with an upward velocity of 48 ft/s. Its height h in feet after t seconds is given by the function

Masja [62]

The equation modeling the height of the ball at time,t is given by h=-16t²+48t+6
a. In how many seconds does the ball reach its maximum height?
Time taken for the ball to reach the maximum height will be given by:
h'(t)=-32t+48=0
finding the value of t we get:
32t=48
t=48/32
t=1.5 seconds
Thus the time taken for the ball to reach the maximum time is 1.5 seconds

b] What is the ball’s maximum height?
The maximum height will be:
h(1.5)=-16(1.5)²+48(1.5)+6
h(1.5)=42 fee

3 0

3 years ago