Answer: -2?
im not 100% sure so please b cautious
Answer:

Step-by-step explanation:
<u>Step 1: Set d to 9 and c to 5
</u>




Answer: 
Choice A is the answer which is the point (1,-1)
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How I got this answer:
Plug each point into the inequality. If you get a true statement after simplifying, then that point is in the solution set and therefore a solution. Otherwise, it's not a solution.
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checking choice A
plug in (x,y) = (1,-1)



This is true because -3 is equal to itself. So this is the answer.
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checking choice B
plug in (x,y) = (2,4)



This is false because 0 is not to the left of -3, nor is 0 equal to -3. We can cross this off the list.
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checking choice C
plug in (x,y) = (-2,3)



This is false because 7 is not to the left of -3, nor is 7 equal to -3. We can cross this off the list.
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checking choice D
plug in (x,y) = (3,4)



This is false because -2 is not to the left of -3, nor is -2 equal to -3. We can cross this off the list.
It could be 3 and lower because if you - 7 from -10 you get -17 then your equation would be -5x< -17 than you divide -17 by -5 and get 3.4 than your equation is x < 3.4 so your answer is 3.4 or below.
Answer:
I hope this makes sense, sorry for the lack of proofs.
Step-by-step explanation:
It is given that S is the midpoint of line QT. The definition of a midpoint is that it bisects the line it is on. So, line QS and line TS are congruent, or the same.
Now, we also know that line QR and line TU are parallel. Because they are parallel, it means that they form congruent corners with lines QS and TS..I think the proof here is "angles opposite to congruent sides are congruent in a triangle." But I'm not sure if this is right. Anyways, this means angles RQS and UTS are congruent.
There's also some proof that when two lines cross, the opposite angles are congruent. This means that angles TSU and QSR are congruent.
Therefore, by ASA (angle-side-angle) ΔQRS ≅ ΔTUS.