(cube root of 5) * sqrt(5)
--------------------------------- = ?
(cube root of 5^5)
This becomes easier if we switch to fractional exponents:
5^(1/3) * 5^(1/2) 5^(1/3 + 1/2) 5^(5/6)
------------------------ = --------------------- = ------------- = 5^[5/6 - 5/3]
[ 5^5 ]^(1/3) 5^(5/3) 5^(5/3)
Note that 5/6 - 5/3 = 5/6 - 10/6 = -5/6.
1
Thus, 5^[5/6 - 5/3] = 5^(-5/6) = --------------
5^(5/6)
That's the correct answer. But if you want to remove the fractional exponent from the denominator, do this:
1 5^(1/6) 5^(1/6)
---------- * ------------- = -------------- (ANSWER)
5^(5/6) 5^(1/6) 5
b=16 , First you multiply 30 by 2 to see what sum you need for the numerator. Then you subtract the 60 that you get by the 12 and get 48. So 3 multiplied by b should give you 48. So you just divide 48 by 3 and get 16.
just divide it is simple bruh
Answer:
x=2.5
Step-by-step explanation:
Solve for x in this systems of equations, we already have two values which equal y so half the work is finished for us.
Starting with the equation:

Add x to both sides to remove the negative x on the right side of the equation:

Subtract 12 from both sides to remove the 12 on the left side of the equation:

Divide both sides by 2 to cancel out the x coefficient

Answer:
Step-by-step explanation:
First box is 7x. second is 7+x,third is x-7 last is 2x +7