The answer is only I and II
-np-4≤2(c-3)
-np-4≤2x-6
-np≤2x-2
-n≤(2x-2)/p
n≥-((2x-2)/p)
Hello from MrBillDoesMath!
Answer:
Positive x-intercept = + sqrt(3)
Negative x-intercept = - sqrt(3)
Discussion:
Generally, the x-intercept of a function g(x) occurs where g(x) = 0. In our case this is
g(x) = 0 =>
3x^2 - 9 = 0 => (add 9 to both sides of the equation)
3 x^2 = 9 => (divide both sides by 3)
x^2 = 9/3 = 3 =>
x = +\- sqrt (3)
Positive x-intercept = + sqrt(3)
Negative x-intercept = - sqrt(3)
Thank you,
MrB
Well what i think you're asking here...I apologie if I'm wrong but what I did was
f(-1) = 4 * 7^t = 4/7
and
f(2) = 4 * 7^t = 196.
Is this what you wanted if not I can...try another way.
Answer:
C.It is a one-tailed test since the alternative hypothesis states that the parameter is greater than the hypothesized value.
Step-by-step explanation:
Let p be the percentage of students enrolled in an introductory Chemistry class dropped before the midterm. Then null and alternative hypotheses are:
: p=10%
: p>10%
The alternative hypothesis states that the parameter is greater than the hypothesized value.
