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My name is Ann [436]
3 years ago
8

Find measure of angles B, E, D and C and the length of BC.

Mathematics
2 answers:
melomori [17]3 years ago
6 0

Answer:

< B = 180-30-65=85°

< E = 85°

< D = 30°

< C = 65°

BC = 20/35 × 28 = 16

choli [55]3 years ago
5 0

Answer:

<D = 30

< C = 65

<B = <E = 85

16 = BC

Step-by-step explanation:

ABC ~ Triangle DEF

<A = <D = 30

< C = <F = 65

Since they are similar triangles

A+ C + B = 180 since the angles of a triangle = 180

30+65+B =180

95+ B = 180

<B = 180 -95 = 85

<B = <E = 85

The triangles are similar so the sides are proportional

AB      BC

----  = ---------

DE      EF

20      BC

----  = ---------

35      28

Using cross products

20*28 = 35 BC

Divide each side by 35

20*28/35 = 35/35 BC

16 = BC

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3 years ago
The average summer temperature in Anchorage is 69°F. If the daily temperature is normally distributed with a standard deviation
mafiozo [28]

Answer:

81.85%

Step-by-step explanation:

Given :

The average summer temperature in Anchorage is 69°F.

The daily temperature is normally distributed with a standard deviation of 7°F .

To Find:What percentage of the time would the temperature be between 55°F and 76°F?

Solution:

Mean = \mu = 69

Standard deviation = \sigma = 7

Formula : z=\frac{x-\mu}{\sigma}

Now At x = 55

z=\frac{55-69}{7}

z=-2

At x = 76

z=\frac{76-69}{7}

z=1

Now to find P(55<z<76)

P(2<z<-1)=P(z<2)-P(z>-1)

Using z table :

P(2<z<-1)=P(z<2)-P(z>-1)=0.9772-0.1587=0.8185

Now percentage of the time would the temperature be between 55°F and 76°F = 0.8185 \times 100 = 81.85\%

Hence If the daily temperature is normally distributed with a standard deviation of 7°F, 81.85% of the time would the temperature be between 55°F and 76°F.

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3 years ago
What is the exact number of 2000
GaryK [48]
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3 years ago
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Verizon [17]
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