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agasfer [191]
3 years ago
5

A client would like this logo printed onto a canvas that is at least 70 inches tall. The original logo is 4.5 inches wide by 3.6

inches tall. Which of the following dimensions will keep the logo in proportion and large enough to meet the clients requirements?
Mathematics
1 answer:
vfiekz [6]3 years ago
4 0

Answer:

87.5 by 70 inches

Step-by-step explanation:

No options were given. So, I will calculate the minimum width

Given

Original\ Logo = 4.5 : 3.6

Height = 70 in ---- of the printed logo

Required

Determine the dimension that keeps the requirement

Let x be the width of the printed logo.

So, the ratio can be represented as:

Printed\ Logo = x : 70

Equate both ratios

x  : 70 = 4.5 : 3.6

As fraction

x  / 70 = 4.5 / 3.6

Multiply through by 70

70 * x  / 70 = 4.5 / 3.6* 70

x = 87.5

So, one of the dimension that meets the requirement is a width of 87.5 inches

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The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 33,208 miles, with a standard
avanturin [10]

Answer:

There is a 92.32% probability that the sample mean would differ from the population mean by less than 633 miles in a sample of 49 tires if the manager is correct.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 33,208 miles, with a standard deviation of 2503 miles.

This means that \mu = 33208, \sigma = 2503.

What is the probability that the sample mean would differ from the population mean by less than 633 miles in a sample of 49 tires if the manager is correct?

This is the pvalue of Z when X = 33208+633 = 33841 subtracted by the pvalue of Z when X = 33208 - 633 = 32575

By the Central Limit Theorem, we have t find the standard deviation of the sample, that is:

s = \frac{\sigma}{\sqrt{n}} = \frac{2503}{\sqrt{49}} = 357.57

So

X = 33841

Z = \frac{X - \mu}{\sigma}

Z = \frac{33841 - 33208}{357.57}

Z = 1.77

Z = 1.77 has a pvalue of 0.9616

X = 32575

Z = \frac{X - \mu}{\sigma}

Z = \frac{32575- 33208}{357.57}

Z = -1.77

Z = -1.77 has a pvalue of 0.0384.

This means that there is a 0.9616 - 0.0384 = 0.9232 = 92.32% probability that the sample mean would differ from the population mean by less than 633 miles in a sample of 49 tires if the manager is correct.

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3 years ago
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maw [93]

Answer:

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Step-by-step explanation:

it has a percent sign

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Answer:

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Step-by-step explanation:

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3 years ago
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If f(x)=x-2 which of the following is the inverse of f(x) brainly
Lostsunrise [7]

Answer:

The inverse of f(x) is  f ^ {- 1}(x) = x + 2

Step-by-step explanation:

To find the inverse of the function f (x) = x-2, perform the following steps:

1) do y = f (x)

y = x-2

2) Solve the equation for the variable x.

y + 2 = x -2 +2

y + 2 = x

3) exchange the variable x with the variable y

y + 2 = x ----> x + 2 = y

4) Change the variable y by f ^{- 1}(x)

Finally the inverse function is:

 f ^ {- 1} (x) = x + 2

4 0
3 years ago
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