Answer:
87.5 by 70 inches
Step-by-step explanation:
No options were given. So, I will calculate the minimum width
Given
Height = 70 in ---- of the printed logo
Required
Determine the dimension that keeps the requirement
Let x be the width of the printed logo.
So, the ratio can be represented as:
Equate both ratios
As fraction
Multiply through by 70
So, one of the dimension that meets the requirement is a width of 87.5 inches
20
Step-by-step explanation
√(25)(16)
find the perpendicular of the angle of pole
x = 26°
The measure of the secant- secant angle x is one- half the difference of the measures of the intercepted arcs , larger subtract smaller
x = (66° - 14°) = 0.5 × 52° = 26°