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Elenna [48]
2 years ago
11

Factor this: 18x^2+39x-15

Mathematics
2 answers:
taurus [48]2 years ago
6 0

Steps for Factoring:

1) Find CM (common factor) for the expression: 3

   Factor out 3 =>

   3(6x^{2}+13x-5)

2)Factor the above expression by grouping:

  The expression needs to be written as 6x^{2} + ax+ bx -5

 a and b should add up to 13 and multiply up to -30 (6 × -5)

By Guess & Check we find that the pair is a = -2 and b = 15 (-2+15; -2 × 15)

3) Now we can rewrite (6x^{2}+13x-5) as (6x^{2} -2x)+(15x-5)\\

Factor out 2x in the first group and 5 in the second group:

2x(3x-1)+5(3x-1)\\

As 3x-1 is on both sides, now we can do the operation: 2x+5 (distributive property)

(3x-1) (2x+5)

The answer is 3(3x-1) (2x+5)

<em>Hope it helps!</em>

frosja888 [35]2 years ago
4 0
Answer is:
3(2x+5)*(3x-1)
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The <em><u>correct answer</u></em> is:

h(t) = –16t² + 50t + 3

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svlad2 [7]

Answer:

a)

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

b)

The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 4,200.00 at a rate of 3.6% per year  compounded 12 times per year  over 10 years is $5667.28.

Step-by-step explanation:

a. Write the function that represents the value of the account at any time, t.

The function that represents the value of the account at any time, t

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

where

P represents the principal amount

r represents Annual Rate

n represents the number of compounding periods per unit t, at the end of each period

t represents the time Involve

b) What will the value be after 10 years?

Given

The principal amount  P = $4200

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Time Period = t

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The total amount A = ?

Using the formula

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

substituting the values

A\:=\:4200\left(1\:+\:\frac{0.003}{12}\right)^{\left(12\right)\left(10\right)}

\:A\:=\:4200\left(1.0025\right)^{120}

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Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 4,200.00 at a rate of 3.6% per year  compounded 12 times per year  over 10 years is $5667.28.

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