A local trucking company fitted a regression to relate the travel time (days) of its shipments as a function of the distance tra
1 answer:
Answer:
Thus; the slope is positive
Step-by-step explanation:
Given that :
the sample size = 20
for the slope; the degree of freedom df = n - 2
= 20 -2
= 18
Using ∝ = 0.05
From t -table , one tailed, at df =18)
Thus the t- critical for the right tailed test is 1.734. This simply refers to the fact that the critical region is test statistics.
Incorporating the Excel Formula [ T.INV (1 - 0.05).18) = 1.734063607
≅ 1.734
You might be interested in
Answer:
The answer is below
Step-by-step explanation:
A) i)
For Anna initially, she has $0 from making 0 envelopes. After making 400 envelopes she has $20. Let x represent the number of envelopes and y the earnings. Hence this can be represented by the points (0, 0) and (400, 20). Using the equation of a line:
The table is:
x: 200 400 600 800 1000
y: 10 20 30 40 50
ii)
For Jason initially, he has $0 from making 0 envelopes. For every 250 envelopes he has $10. Let x represent the number of envelopes and y the earnings. Hence this can be represented by the points (0, 0) and (250, 10). Using the equation of a line:
The table is:
x: 200 400 600 800 1000
y: 8 16 24 32 40
The graph is plotted using geogebra online graphing
b) From the table above we can see that Anna makes more stuffing than Jason.
c) Anna has a savings of $100. Hence this can be represented by the points (0, 100) and (250, 10). Using the equation of a line:
We can see from the graph that there is a y intercept at 100. That is the earnings starts from 100.
The equation of a line is given as y = mx + b, where m is the slope and b is the y intercept (initial value)
For the first graph, the slope is 1/20 and the initial value is 0 while for the second graph the slope is 1/15 and the initial value is 100
D) The line pass through (10, 10) and (100, 40), hence:
