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Bezzdna [24]
3 years ago
6

A rectangular garden has an area of 60 squared feet. The garden is 4 feet longer than it is wide. Which equation can be used to

determine the length and width of the garden?
Mathematics
1 answer:
Drupady [299]3 years ago
5 0

Answer: See explanation

Step-by-step explanation:

Let the width be x

Then, the length will be x+4

Area = Length × Width

Therefore,

x × (x+4) = 60

x² + 4x = 60

x² + 4x - 60 = 0

x² + 10x - 6x - 60 = 0

x(x + 10) - 6(x + 10) = 0

(x - 6)(x + 10) = 0

x - 6 = 0

x = 6

The width is 6feet

Length = 6+4 = 10 feet

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x =\frac{4}{3}inch is the size in wheels on the scale model .

<u>Step-by-step explanation:</u>

Correct Question : Tom has a scale model of his car. The scale factor is 1 : 12. If the actual car has 16-inch wheels, what size are the wheels on the scale model?

We have , The scale factor is 1 : 12. We need to find If the actual car has 16-inch wheels, what size are the wheels on the scale model .Let's find out:

Ratio of size of wheels to actual size of wheels is 1:12 , but actual car has 16-inch wheels So ,

⇒ \frac{1}{12}  = \frac{x}{16}                 { x is size of wheel in scale model }

⇒ \frac{1(16)}{12}  = \frac{x}{16}(16)

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4 years ago
K = 8k + 28<br><br> I'm confused, please help me!
AveGali [126]
K=8k+28

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3 0
4 years ago
WHY IS THIS GETTING DELETED?? I NEED HELP
aliina [53]

If this exact question is repeatedly deleted, it's probably because of the ambiguity of the given equation. I see two likely interpretations, for instance:

\dfrac{(5\times5)^k}{5^{-8}} = 5^3

or

\dfrac{5\times 5^k}{5^{-8}} = 5^3

If the first one is what you intended, then

\dfrac{(5\times5)^k}{5^{-8}} = \dfrac{(5^2)^k}{5^{-8}} = \dfrac{5^{2k}}{5^{-8}} = 5^{2k-(-8)} = 5^{2k+8} = 5^3

and it follows that

2<em>k</em> + 8 = 3   ==>   2<em>k</em> = -5   ==>   <em>k</em> = -5/2

If you meant the second one, then

\dfrac{5\times 5^k}{5^{-8}} = \dfrac{5^1\times5^k}{5^{-8}} = \dfrac{5^{k+1}}{5^{-8}} = 5^{k+1-(-8)} = 5^{k+9} = 5^3

which would give

<em>k</em> + 9 = 3   ==>   <em>k</em> = -6

And for all I know, you might have meant some other alternative... When you can, you should include a picture of your problem.

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3 years ago
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