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Alenkasestr [34]
3 years ago
5

Which of the following is the correct factored form of the given equation?

Mathematics
2 answers:
katrin [286]3 years ago
6 0

Hint: "4x 2 - 25 = 0" is nearly meaningless. You want 4x^2 - 25 = 0.

Note that both 4x^2 and 25 are perfect squares, so this is the difference of two squares, and is equal to (2x-5)(2x+5)= 0.

dmitriy555 [2]3 years ago
4 0

There is a small subset of polynomials whos factorizations mathematicians like to label "special." From an outside perspective, nothing seems to be different about these polynomials. You can use the same algorithm you use to find any other factorization, but you could also form a general statement about polynomials like this.

This polynomial is in the form a^2-b^2. We can factor this normally.

-b and b add to 0 and multiply to -b^2, so:

a^2+ab-ab-b^2=\\ a(a+b)-b(a-b)=\\ (a-b)(a+b)

So, we've factored this quadratic like we would any other, but we also notice something interesting about all quadratics in this form. In this example,

a^2=4x^2\\ b^2=25

That means

a=2x\\ b=5

So we can say that the factorization of the quadratic is:

(2x-5)(2x+5)

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3 0
3 years ago
If SDE ~ SWT, find WT.
faust18 [17]

Formula used: 40+x = 4x-3 x is used for <em>ET</em>

Step-by-step explanation:

40+x = 4x-3

<u>+</u><u>3</u> <u>+</u><u>3</u>

43+x = 4x

<u>-</u><u>x</u> <u>-</u><u>x</u>

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3 3

14.3 = x

then substitude this on 5x+3 on <em>W</em><em>T</em> and you arr good

5 0
3 years ago
Suppose the line of best fit for some data points has a slope of 4.915. If the mean of the x-coordinates of the data points is 1
8_murik_8 [283]
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Read 2 more answers
Really need an answer to this please help.
Alex

Answer:

a

Step-by-step explanation:

\sqrt[4]{144a^{12}b^{3}} = \sqrt[4]{4^{2}*3^{2}a^{12}b^{3}}=\\= \sqrt[4]{2^{4}*3^{2}a^{12}b^{3}}=2a^{3}\sqrt[4]{3^{2}b^{3}} =\\}=2a^{3}\sqrt[4]{9b^{3}}

7 0
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Assume the mean life of an iPhone is 5 years (60 months)and a standard deviation of 8 months If the age in years at which an iPh
melamori03 [73]

Answer:

Answer:

safe speed for the larger radius track u= √2 v

Explanation:

The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.

Also given that r_1= smaller radius

r_2= larger radius curve

r_2= 2r_1..............i

let u be the speed of larger radius curve

now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=

r

1

mv

2

=

r

2

mu

2

................ii

form i and ii we can write

v^2= \frac{1}{2} u^2v

2

=

2

1

u

2

⇒u= √2 v

therefore, safe speed for the larger radius track u= √2 v

8 0
2 years ago
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