There is a small subset of polynomials whos factorizations mathematicians like to label "special." From an outside perspective, nothing seems to be different about these polynomials. You can use the same algorithm you use to find any other factorization, but you could also form a general statement about polynomials like this.
This polynomial is in the form a^2-b^2. We can factor this normally.
-b and b add to 0 and multiply to -b^2, so:
So, we've factored this quadratic like we would any other, but we also notice something interesting about all quadratics in this form. In this example,
That means
So we can say that the factorization of the quadratic is:
Answer:
The coordinates are and
.
Step-by-step explanation:
First, we have to derive an expression for translation under the assumption that each point of XYZ experiments the same translation. Vectorially speaking, translation from X to X' is defined by:
(1)
Where is the vector translation.
If we know that and
, then the vector translation is:
Then, we determine the coordinates for Y' and Z':
The coordinates are and
.