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3 years ago

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One day there is an accident and the tank cracks in 4 places. Water flows out of each crack at a rate of 12 liter per hour. An e

mergency pump can refill the tank at a rate of 2 liters per minute.

1 answer:

valentinak56 [21]3 years ago

5 0

What’s the question?

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Y is a differentiable function of x. Choose the alternative that is the derivative dy / dx.

murzikaleks [220]

Differentiating both sides of

$x^3-y^3=1$

with respect to <em>x</em> yields (using the chain rule)

$3x^2 - 3y^2 \dfrac{\mathrm dy}{\mathrm dx} = 0$

Solve for d<em>y</em>/d<em>x</em> :

$3x^2 - 3y^2 \dfrac{\mathrm dy}{\mathrm dx} = 0 \\\\ 3y^2\dfrac{\mathrm dy}{\mathrm dx} = 3x^2 \\\\ \dfrac{\mathrm dy}{\mathrm dx} = \dfrac{3x^2}{3y^2} = \dfrac{x^2}{y^2}$

The answer is then D.

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2 years ago

C=59(f-32) solve for f

Amiraneli [1.4K]

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3 years ago

Domain and range of the function and it’s inverse

sineoko [7]

Answer:

B (second table in list)

Step-by-step explanation:

The function is a quadratic with vertex and y-intercept at (0,-2). The parabola opens up meaning only y - values above -2 are a part of the function. Since range is the set of all y values, then the range is $y\geq -2$ .

The domain is not restricted and it is all real numbers.

The inverse of the function is where x and y are switched. So the range becomes the domain and vice verse.

This means the domain of the inverse is $x\geq -2$ and the range of the inverse is all real numbers.

8 0

3 years ago

What is the value of the fourth term in a geometric sequence for which a1 = 30 and r = 1/2?

Pani-rosa [81]

Answer: The required fourth term of the geometric sequence is $\dfrac{10}{9}.$

Step-by-step explanation: We are given to find the value of the fourth term in a geometric sequence with first term and common ratio as follows :

$a(1)=30,~~~~~r=\dfrac{1}{2}.$

We know that

the n-th term of a geometric sequence with first term a1 and common ratio r given by

$a(n)=a(1)r^{n-1}.$

Therefore, the fourth term of the given geometric sequence will be

$a(4)=a(1)r^{4-1}=30\times r^3=30\times\left(\dfrac{1}{3}\right)^3=\dfrac{30}{27}=\dfrac{10}{9}.$

Thus, the required fourth term of the geometric sequence is $\dfrac{10}{9}.$

7 0

3 years ago

Read 2 more answers

Can someone help me with this and explain please

Artyom0805 [142]

X/y = 2 so x = 2y
z/x = 4 so z = 4x but x = 2y so z = 4(2y) = 8y

now you have
x = 2y, z = 8y

x + y + z 2y + y + 8y 11y 11
------------ = -----------------------= ------------- = ----------- = 5 1/2
x 2y 2y 2

answer
C. 5 1/2

6 0

3 years ago