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Murrr4er [49]
3 years ago
5

The polynomial fx) is written in factored form:

Mathematics
1 answer:
Elan Coil [88]3 years ago
4 0

Answer:

ghhhhhhhhgffgffdddghvcchcfzdxx

Step-by-step explanation:

hhhhgggygfggyggg

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Un teren de 220 ha trebuie arat in 3 zile.Stiind ca a doua zi s-a arat de 1,5 ori mai mult ca in frima zi,iar in a treia zi s-a
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I need a translation
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Given that AB parallels QR, AB bisects AE, QR bisects QT
enyata [817]

Answer:

  1. Dilate ΔABE by a factor of 2/5 to make ΔA'B'E'

  2. Translate A' to Q

Step-by-step explanation:

We notice the triangles have the same orientation, so no reflection or rotation is involved. The desired mapping can be accomplished by dilation and translation:

  1. Dilate ΔABE by a factor of 2/5 to make ΔA'B'E'

  2. Translate A' to Q

The result will be that ΔA"B"E" will lie on top of ΔQRT, as required.

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3 years ago
Pls help extra points and mark brainlist
vladimir1956 [14]

Answer:

it d j=6

Step-by-step explanation:

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48/8

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7 0
3 years ago
Read 2 more answers
What is the common difference between the terms in the following sequence?
Ipatiy [6.2K]

Answer:

-6

Step-by-step explanation:

17-6=11

11-6=5

5-6=-1

-1-6=-7

6 0
2 years ago
Read 2 more answers
Joy recorded the distances she walked each day for five days. How far did she walk in 5 days? Line plot: 3 xs on 1/3 1 x on 1/2
kotykmax [81]

Answer:

2\frac{1}{6}\approx 2.167 units.

Step-by-step explanation:

We have been given that Joy recorded the distances she walked each day for five days.

To find the distance traveled be Joy in 5 days we will add the distances covered by Joy each day.

As there are 3 dots on 1/3, this means that Joy traveled 1/3 units on 3 days.

Since there is 1 dot on 1/2 and on dot on 2/3, so this means that Joy walked 1/2 units one day and 2/3 units another day.

Let us add all these distances.

\text{Total distance walked by Joy in 3 days}=3\times\frac{1}{3}+\frac{1}{2}+\frac{2}{3}

\text{Total distance walked by Joy in 3 days}=\frac{1*3}{3}+\frac{1}{2}+\frac{2}{3}

Let us have a common denominator.

\text{Total distance walked by Joy in 3 days}=\frac{3*2}{3*2}+\frac{1*3}{2*3}+\frac{2*2}{3*2}

\text{Total distance walked by Joy in 3 days}=\frac{6}{6}+\frac{3}{6}+\frac{4}{6}

\text{Total distance walked by Joy in 3 days}=\frac{6+3+4}{6}

\text{Total distance walked by Joy in 3 days}=\frac{13}{6}

\text{Total distance walked by Joy in 3 days}=2\frac{1}{6}

Therefore, Joy traveled 2\frac{1}{6}\approx 2.167 units in 5 days.

8 0
4 years ago
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