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3 years ago

Based on the graph shown to the right, whose phones cost varies directly with the amount of time spent talking?

Mathematics

2 answers:

Lena [83]3 years ago

8 0

Answer:

Step-by-step explanation:

Given 2 quantities that vary directly, then the graph must pass through the origin.

Nikiya's graph is the only one to do this ⇒ B

sineoko [7]3 years ago

6 0

Answer:

B. Nikiya's only

Step-by-step explanation:

Mark’s cost does not vary directly with time spent talking because the cost of 0 hours is not 0 dollars

For Nikiya’s plan, the value of the constant of variation is 15

which represents Nikiya’s cost per hour

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0.09 is 10 Times as much as

Mumz [18]

0.09/10=0.009
we check it: 0.009*10=0.09, so it's right

8 0

3 years ago

Solve for x. 6x + 5 = -x + 40 B. x= -5 A. x = -9 D. x= 9 C. x = 5

denis23 [38]

C, x=-5, hope this helps

3 0

3 years ago

Find the sum of the counting numbers from 1 to 25 inclusive. In other words, if S = 1 + 2 + 3 + ... + 24 + 25, find the value of

Anastaziya [24]

Answer:

325

Step-by-step explanation:

You must have heard about Arithmetic Progressions (AP)

Arithmetic progressions are a series of numbers such that every successive number is the sum of a constant number and the previous number.

Our very own counting numbers form AP

For example :-

2 = 1 + 1

3 = 2 + 1

4 = 3 + 1

The number in bold (1) is that constant number which is added to a number to form its successive number.

To find the sum of series forming AP, we use the formula :-

$sum = \frac{n}{2} \{ a + a _{n} \}$

here,

n is the number of terms
a is the first number of the series
an is the last number of the series

So we'll use all this information to find the sum of continuous numbers from 1 to 25 where 1 is the first term(a) and 25 is the last(an).

and n is 25

$S = \frac{25}{2}\{ 1 +25\}$

$= \frac{25 \times 26}{2}$

$= 25 \times 13$

$= 325$

So, the value of S comes out to be 325.

8 0

3 years ago

Read 2 more answers

Quick! Need help, anyone know this?

andrey2020 [161]

It is the second option or b

6 0

3 years ago

Which expression is equivalent to RootIndex 3 StartRoot 32 x Superscript 8 Baseline y Superscript 10 Baseline EndRoot?

evablogger [386]

Answer:

The equivalent expression to the given expression is $\sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}$

Step-by-step explanation:

The given expression is $\sqrt[3]{32x^8y^{10}}$

To find the equivalent expression:

$\sqrt[3]{32x^8y^{10}}=(32x^8y^{10})^{\frac{1}{3}}$

We may write the above expression as below:

$=(32^{\frac{1}{3}})((x^8)^{\frac{1}{3}})((y^{10})^{\frac{1}{3}})$

$=(2)((4)^{\frac{1}{3}})(x^6)\times (x^2)(x^{\frac{2}{3}})(y^3)(y^{\frac{1}{3}})$ (using square root properties)

$=(2\sqrt[3]{4})(x^2\sqrt[3]{x^2})(y^3\sqrt[3]{y})$ (combining the like terms and doing multiplication )

$=2x^2y^3\sqrt[3]{4x^2y}$

Therefore $\sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}$

Therefore the equivalent expression to the given expression is $\sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}$

5 0

3 years ago

Read 2 more answers