Answer:
18 units
Step-by-step explanation:
(-4 , 10) and (-4, -8)
Distance = 
![= \sqrt{(-4-[-4])^{2}+(-8-10)^{2}}\\\\= \sqrt{(-4+4)^{2}+(-18)^{2}}\\\\=\sqrt{0 + 324}\\\\=\sqrt{324}\\\\= 18](https://tex.z-dn.net/?f=%3D%20%5Csqrt%7B%28-4-%5B-4%5D%29%5E%7B2%7D%2B%28-8-10%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%20%5Csqrt%7B%28-4%2B4%29%5E%7B2%7D%2B%28-18%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B0%20%2B%20324%7D%5C%5C%5C%5C%3D%5Csqrt%7B324%7D%5C%5C%5C%5C%3D%2018)
Answer:
Step-by-step explanation:
By using mid point formula ,
(X,Y) =( X1+X2/2) , Y1 +Y2/2
(-2+2/2) , (-4-10/2)
or, (0/2), (-7)
A + C
(-5, -7) is 7 units to the left of point H
(-7, 7) is more than 7 units up and left of point H
the x axis is at (infinity, 0), being only 7 points up from point H
Answer:
9^7
Step-by-step explanation:
7*2=9
When atleast one dice shows a 6 the possible outcomes will be:
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
(1,6), (2,6), (3,6), (4,6), (5,6)
Thus there are 11 total possible outcomes.
Among these outcomes, the sum of numbers greater than or equal to 9 can be obtained from:
(6,3), (6,4), (6,5), (6,6), (3,6), (4,6), (5,6)
This means there are 7 outcomes with sum greater than or equal to 9.
Thus, Probability of rolling a number greater than or equal to 9 with atleast one dice showing a 6 = 9/11
So, option A gives the correct answer