To solve for this, we need to find for the value of x
when the 1st derivative of the equation is equal to zero (or at the
extrema point).
So what we have to do first is to derive the given
equation:
f (x) = x^2 + 4 x – 31
Taking the first derivative f’ (x):
f’ (x) = 2 x + 4
Setting f’ (x) = 0 and find for x:
2 x + 4 = 0
x = - 2
Therefore the value of a is:
a = f (-2)
a = (-2)^2 + 4 (-2) – 31
a = 4 – 8 – 31
a = - 35
A contraction would make the image smaller.
A negative number reflects the image and changes the size based on the number.
To make an image smaller the factor needs to be less than 1
so -0.5 and 0.5 would make the image smaller since 0.5 is less than 1.
Answer:
13/10
Step-by-step explanation:
Its 13/10...
please give brainliest
Answer:
D. 12.3 ft
Step-by-step explanation:
This problem requires the use of trigonometric ratios. This one specifically uses the cosine ratio as it provides the hypotenuse and is asking for the side that is adjacent to the angle.
cos(40°)=a/16
cos(40°)×16=a/16×16
cos(40°)×16=a
a=12.256 ft
The length of side a is D. 12.3 ft.
my guess would be c. but id wait for someone else to answer just to be sure
